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Likurg_2 [28]
3 years ago
6

Three charges are arranged in an equilateral triangle with sides of 4 cm. The coordinates and corresponding charge values are as

follows: +4q at (-2,0); +2q at (2,0); -q at (0,a). The elementary charge of an electron is given by q = -1.602 x 10^-19 C.
a) Determine the y-coordinate a of the third charge

b) Determine the electric field at the centre of the equilateral triangle

c) Determine the torque that acts on the dipole and the work done to align the dipole depicted in the picture the center of the equilateral triangle with the resulting field at the corner. The dipole exhibits a dipole ...?
Mathematics
1 answer:
lisov135 [29]3 years ago
6 0
To determine the answer of Part A draw the equilateral triangle and the to determine the coordinates of of the third charge use that triangle.
To calculate the gravitational field strength in part B from each of the charges use the following equation.

E=kcq/r2

If you would add those values then you can use the symmetry about the y axis to make the vector addition a litter easier.<span />
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ETHANHUNT HELP HERE WOULD BE APPRECIATED
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Length of Image = 9 * 2 = 18

In short, Your Answer would be 18 cm

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Mind giving me help on this?? :0
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What is the value of the expression if m = –5 and n = 3? Negative StartFraction 24 Over 25 EndFraction Negative StartFraction 4
KatRina [158]

You can use the fact that  a number raised to negative powers can be written as 1 divided by that number raised to positive number.

The value of the given expression when m = -5 and n= 3 is -\dfrac{2}{5}

<h3>How can we rewrite a number raised to negative power?</h3>

Suppose we've got a^{-b} . then it can be rewritten as

a^{-b}  = \dfrac{1}{a^b}

It is because a^0 = 1 for any a except 0, and that  \dfrac{a^0}{a^b} = a^{0-b} = a^{-b}

If base are same and there is multiplication, then there will be addition in power.

Also, know the fact that if base are same and there is division, there will be subtraction in power(subtracting since that denominator when goes up, its power gets negated(gets negative sign to the existing power)

Thus,

a^b \timesa ^c = a^{b+c}\\\\\dfrac{a^b}{a^c} = a^{b-c}

<h3>Using above method to simplify the given expression before evaluating</h3>

The given expression is \dfrac{2m^{-1}n^5}{3m^0n^4} = \dfrac{2n^5}{3m^0m^1n^4} = \dfrac{2n^5}{3mn^4} = \dfrac{2n^{5-4}}{3m} = \dfrac{2n^1}{3m} = \dfrac{2n}{3m}

Putting m = -5 and n=3, we get:

\dfrac{2\times 3}{3 \times -5} = -\dfrac{2}{5}

Thus,

The value of the given expression when m = -5 and n= 3 is -\dfrac{2}{5}

Learn more about base and exponent(power) here:

brainly.com/question/847241

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3 years ago
Problem: Which expressions are equivalent to 2(x - 7)?
Yakvenalex [24]
Answer:2x-14. Explanation: distribute 2 to both terms
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3 years ago
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