So you move left to right like PEMDAS when it comes to adding or subtracting either or could go first and same thing applies with multiplying and dividing so for instance in this case

47*7=329
_
329/9=36.5

3 0

3 years ago

11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *

kompoz [17]

Answer:

$c=0.4\ J/g^{\circ} C$

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C$

So, the specific heat of the material is $0.4\ J/g^{\circ} C$ .

3 0

3 years ago

Help please will mark brainliest!!!!!!

Nimfa-mama [501]

<h3>Solution : </h3>

$\bf Speed = \dfrac{\dfrac{4}{5}}{\dfrac{1}{6}}$

$\bf Speed = \dfrac{4}{5} \times \dfrac{6}{1}$

$\Large \boxed{\bf Speed = \dfrac{24}{5}}$

$\pink{\bf So, \: the \: answer \: is \: \dfrac{24}{5} \: miles \: per \: hour}$

5 0

2 years ago

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