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AVprozaik [17]
3 years ago
7

Oatmeal costs $1.73/lb. How much would 2.6 lb of oatmeal cost?

Mathematics
2 answers:
weeeeeb [17]3 years ago
7 0
It would cost about $4.50
nasty-shy [4]3 years ago
6 0
$4.49
muliply the pounds by the cost
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Which figures will have a volume that is greater than 100 cubic units? Select two options.
igor_vitrenko [27]

Answer:

B and D

Step-by-step explanation:

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1 year ago
The hyperloop would be able to travel 1,050 miles in 1 1/2 hours. how long would it take the acela train to travel that far?
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3 years ago
A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0
3 years ago
The owner of a fish market has an assistant who has determined that the weights of catfish are normally distributed, with mean o
prohojiy [21]

Answer:

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

Step-by-step explanation:

For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:

Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4

For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5

For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0

P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.

The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%

6 0
3 years ago
Caroline earns $54 for 6 hours of babysitting. What is Caroline's rate in dollars per hour?
Elena L [17]

Answer:

Divided 54 divided by 6 = 9

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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