<h2>
The race is 1.2 miles long</h2>
Step-by-step explanation:
The first leg is 3/10 mi, the second leg is 1/2 mi, and the third leg is 2/5 mi.

Now we need to find length of race

The race is 1.2 miles long
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for

is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of

is always positive for

. That means at

there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function

is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
Linear function 2x+3y=12 .
Step-by-step explanation:
To find y-intercept , make x=0 :
3y = 12
y = 12/3
y = 4 .
To find x-intercept , make y=0 :
2x = 12
x = 12/2
x = 6 .
<u> ! Hope this will help you !</u>