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Stels [109]
3 years ago
8

Substitute t = 3 and t = 6 to determine if the two expressions are equivalent.

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
8 0

Answer

Option A: The value of both expressions when t = 3 is 33.

Option D: The value of both expressions when t = 6 is 51.

Option E: The two expressions are equivalent.

Step-by-step explanation

♡ ∩_∩

(„• ֊ •„)♡

┏━∪∪━━━━┓

♡ good luck 。 ♡

┗━━━━━━━┛

Usimov [2.4K]3 years ago
4 0

Answer:

If t= 6

3 (2 x 6 + 5) 6 x 6 + 15

3 (12+5) 36 + 15

3 x 17 =51

= 51

The value of both expressions when t=6 is 51

When t = 3

3(2 x 3 + 5) 6 x 3 + 15

3 (6 +5) 18 + 15

3 x 11 =33

= 33

The value of both expressions when t= 3 is 33

Step-by-step explanation:

Step-by-step explanation:

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Consider the following division of polynomials.
Bond [772]

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and subtracting this from the previous remainder gives a new remainder of

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What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

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To verify this solution, we can simply multiply this by the original denominator:

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=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

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2 years ago
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Maslowich
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Answer:x=2

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5 0
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