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kozerog [31]
3 years ago
13

Raheem made a net of a triangular pyramid as shown.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer:

the answer is b

Step-by-step explanation:

i took the test it is b. The sum of the areas of faces A, B, and C.

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Is y=7x+12 linear or nonlinear?
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Yes, I think it is

because the equation has a horizontal line

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M(-5, 2) and N(5, 2) are the endpoints of the segment MN on the coordinate plane. What is the length of ?
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The line segment is 10 units long
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What method can you use to find the product of 70×55
IceJOKER [234]
You can use the regrouping
6 0
4 years ago
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
Mark studied a group of 30 whales. If each will wait approximately 3.8×10 to the fifth power, pounds find the total weight of al
natta225 [31]

Answer:

11.4 x 10 ^ 6

Step-by-step explanation:

  1. First, you have to convert 3.8 x 10^5 out of scientific notation. To do that, multiply 3.8 * 10^5, you'll get 380,000. This is the weight of each whale.
  2. Now multiply the weight of each whale times 30. 380,000 * 30 = 11,400,000
  3. Convert back to scientific notation. 11.4 x 10^6
7 0
3 years ago
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