a skydiver jumps out from the plane at 10,000 feet above the ground. the skydiver decends at a rate of 175 feet per seconds. how
high in the air is the skydiver when he opens his parachute after 25 seconds?
2 answers:
Answer:
5625 feets
Step-by-step explanation:
Rate(feet/seconds) = height(feets)/time(seconds)
175 = x/25
x = 4375
After the skydiver opens his parachute the height reduces
Initial height – reduced height
10000 – 4375
= 5625 feets
Answer:
5625 feet
I hope it's helps you
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