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ioda
3 years ago
12

a skydiver jumps out from the plane at 10,000 feet above the ground. the skydiver decends at a rate of 175 feet per seconds. how

high in the air is the skydiver when he opens his parachute after 25 seconds?
Mathematics
2 answers:
goldenfox [79]3 years ago
8 0

Answer:

5625 feets

Step-by-step explanation:

Rate(feet/seconds) = height(feets)/time(seconds)

175 = x/25

x = 4375

After the skydiver opens his parachute the height reduces

Initial height – reduced height

10000 – 4375

= 5625 feets

nikitadnepr [17]3 years ago
5 0

Answer:

5625 feet

I hope it's helps you

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