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Svetllana [295]
3 years ago
8

The lists below gives the donations, in dollars that two different charities received in 1 day. Compare the means of the two dat

a sets. Show all work and explain your final answer. Planted Society: 40,20,16,20,17,12,15 Bees Park Expansion: 25,12,9,15,35,20,6,30
Mathematics
1 answer:
icang [17]3 years ago
6 0

Answer:

The mean of Planted Society's donations received is higher than Bees Park Expansion's.

Step-by-step explanation:

To get the mean, you want to add all of the numbers up and divide by how many numbers up. For example, you add all of the values for Planted Society and get 140. We know that there are 7 numbers given, so we do 140 divided by 7 to get a mean of 20. Same with Bees Park Expansion; add to get a total of 152. There are 8 numbers, and 152 divided by 8 is 19. This means 20>19. Mean is also written as average in questions.

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3600<br> in standard<br> form
slavikrds [6]

Answer:

3.6 x 10^3

Step-by-step explanation:

4 0
3 years ago
you can buy a 1.5 lbs bag of gummy bear for $4.35 or spend $5.30 for 2 lbs of gummy bears. Which of the bags is a better deal?
alukav5142 [94]

Answer:

The 2 pound bag of gummy bears

Step-by-step explanation:

You do 1.5/4.35 which = 2.9 the 2.9 is $2.90 per pound

Then, you do 5.3/2 which = 2.6 this 2.6 is $2.60 per pound

$2.60 <  $2.90 there for the 2 pound bag of gummy bears is the better deal

3 0
3 years ago
How would you describe the difference between the graphs of f(x) = x2 +4 and<br> G(y) = y2 +4 ?
ivann1987 [24]

Answer:

They're the exact same, except for the variables.

Step-by-step explanation:

Since the variable can be any letter, it is the exact same equation but with different letters as x. Although the equation of G(y) has a y instead of x, you know y is the x and g(y) is the y because the y inside of the parentheses tells us that y is the independent variable.

5 0
3 years ago
How do you find the volume of the solid generated by revolving the region bounded by the graphs
d1i1m1o1n [39]

Answer:

About the x axis

V = 4\pi[ \frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}

About the y axis

V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}

About the line y=8

V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}

About the line x=2

V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi

Step-by-step explanation:

For this case we have the following functions:

y = 2x^2 , y=0, X=2

About the x axis

Our zone of interest is on the figure attached, we see that the limit son x are from 0 to 2 and on  y from 0 to 8.

We can find the area like this:

A = \pi r^2 = \pi (2x^2)^2 = 4 \pi x^4

And we can find the volume with this formula:

V = \int_{a}^b A(x) dx

V= 4\pi \int_{0}^2 x^4 dx

V = 4\pi [\frac{x^5}{5}] \Big|_0^2 =4\pi *\frac{32}{5}= \frac{128 \pi}{5}

About the y axis

For this case we need to find the function in terms of x like this:

x^2 = \frac{y}{2}

x = \pm \sqrt{\frac{y}{2}} but on this case we are just interested on the + part x=\sqrt{\frac{y}{2}} as we can see on the second figure attached.

We can find the area like this:

A = \pi r^2 = \pi (2-\sqrt{\frac{y}{2}})^2 = \pi (4 -2y +\frac{y^2}{4})

And we can find the volume with this formula:

V = \int_{a}^b A(y) dy

V= \pi \int_{0}^8 2-2y +\frac{y^2}{4} dy

V = \pi [4y -y^2 +\frac{y^3}{12}] \Big|_0^8 =\pi *\frac{32}{3}= \frac{32 \pi}{3}

About the line y=8

The figure 3 attached show the radius. We can find the area like this:

A = \pi r^2 = \pi (8-2x^2)^2 = \pi (64 -32x^2 +4x^4)

And we can find the volume with this formula:

V = \int_{a}^b A(x) dx

V= \pi \int_{0}^2 64-32x^2 +4x^4 dx

V = \pi [64x -\frac{32}{3}x^3 +\frac{4}{5}x^5] \Big|_0^2 =\pi *(128-\frac{256}{3} +\frac{128}{5})= \frac{1024 \pi}{5}

About the line x=2

The figure 4 attached show the radius. We can find the area like this:

A = \pi r^2 = \pi (\sqrt{\frac{y}{2}})^2 = \pi\frac{y}{2}

And we can find the volume with this formula:

V = \int_{a}^b A(y) dy

V= \frac{\pi}{2} \int_{0}^8 y dy

V = \frac{\pi}{2} [\frac{y^2}{2}] \Big|_0^8 =\frac{\pi}{4} *(64)= 16\pi

6 0
3 years ago
Three guinea pigs living in the same cage need at least 12 square feet of living space. Is a cage that measures 3 feet by 5 feet
Basile [38]
Area of the cage : A = L * W
A = 3 * 5
A = 15 sq ft....so ur cage is 15 square ft...and they need at least 12 sq ft...so yes, it is big enough
3 0
3 years ago
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