Answer:
B
Step-by-step explanation:
PEMDAS
8 + 2^3 x 5
8 + 8 x 5
8 + 40
48
Answer:
L = 2w
A = L*W
A = 2w*w
A = 2w^2
Step-by-step explanation:
Answer:
a. 
b. 
Step-by-step explanation:
First, we need tot find a general expression for the amount of caffeine remaining in the body after certain time. As the problem states that every hour x percent of caffeine leaves the body, we must substract that percentage from the initial quantity of caffeine, by each hour passing. That expression would be:

Then, to find the amount of caffeine metabolized per hour, we need to differentiate the previous equation. Following the differentiation rules we get:

The rate is negative as it represents the amount of caffeine leaving the body at certain time.
Answer:
hello!
Step-by-step explanation:
I say u can go for option B
hope it helps!
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