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4 years ago

What is the following difference? 11√45 - 4√5 (picture attached)

Mathematics

2 answers:

asambeis [7]4 years ago

7 0

<span>The answer is 29√5.
</span>
Since 11√45 and 4√5 do not share a common radical, you cannot subtract them. By looking at the equation, you can see that 11√45 is not fully simplified yet by the 45 within the square root.
Breaking it up into squares, you can find that 3 x 3 x 5 = 45, which can be translated into 3<span>² x 5</span>. Since the 3 is a square component in the 45, you can now extract it. Extract the 3 by dividing it from the 45 within the square root and multiplying it into the 11.
Your result is a 33√5, which shares a common radical with 4√5. You can now subtract 33√5 and 4√5, which is 29√5.

Side note: I noticed you got the answer wrong because you chose 7√40. I presume it's because you subtracted the components individually. I suggest that you look up lessons about simplifying radicals, along with adding and subtracting them. Hope this helps!

Maslowich4 years ago

4 0

Answer:

The correct answer is option C , 29 √5

Step-by-step explanation:

11√45 - 4√5

If we simplify the term 11√45 , we get

=11√(9 x5)

= 11√(32 x 5)

= 11 x 3 √5

= 33 √5

Now on subtracting the two numbers, we get –

33 √5 - 4√5

= (33 -4) √5

= 29 √5

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Simplify the quotient . 4.5*10^3/9x10^7 Write your answer in scientific notation. Show your work.

drek231 [11]

Answer:

Simplified from of given quotient is : $\frac{1}{2}*10^{-4}$

Step-by-step explanation:

We have given,

A quotient : $\frac{4.5*10^{3} }{9*10^{7} }$

We can simplify this quotient as:

$\frac{4.5*10^{3} }{9*10^{7} }$

or $\frac{1*10^{3} }{2*10^{7} }$

or $\frac{1}{2}*10^{3-7}$

or $\frac{1}{2}*10^{-4}$

This is the answer.

5 0

4 years ago

Suppose you want to build a small walkway around your garden so that there is someplace to walk around and work on your vegetabl

wolverine [178]

Answer:

Approximately 3.5 feet - Option B

Step-by-step explanation:

Imagine that you have this walkway around the garden, with dimensions 30 by 20 feet. This walkway has a difference of x feet between it's length, and say the dimension 30 feet. In fact it has a difference of x along both dimensions - on either ends. Therefore, the increases length and width should be 30 + 2x, and 20 + 2x, which is with respect to an increases area of 1,000 square feet.

( 30 + 2x ) $*$ ( 20 + 2x ) = 1000 - Expand "( 30 + 2x ) $*$ ( 20 + 2x )"

600 + 100x + 4 $x^2$ = 1000 - Subtract 1000 on either side, making on side = 0

4 $x^2$ + 100x - 400 = 0 - Take the "quadratic equation formula"

( Quadratic Equation is as follows ) - $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ,

$x=\frac{-100+\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad \frac{5\left(\sqrt{41}-5\right)}{2}$ ,

$x=\frac{-100-\sqrt{100^2-4\cdot \:4\left(-400\right)}}{2\cdot \:4}:\quad -\frac{5\left(5+\sqrt{41}\right)}{2}$

There can't be a negative width of the walkway, hence our solution should be ( in exact terms ) $\frac{5\left(\sqrt{41}-5\right)}{2}$ . The approximated value however is 3.5081...or approximately 3.5 feet.

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3 years ago

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MaRussiya [10]

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5 0

3 years ago

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Gnom [1K]

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3 years ago

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vazorg [7]

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