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RSB [31]
3 years ago
14

For questions 1 and 2 graph the exponential function: 1. y=3^x 2. y=2(4.5)^x

Mathematics
2 answers:
Mumz [18]3 years ago
5 0
First, we should know exponential formula, for example exp (LnA) =A, for all A>0, and as for logarythm, LnA^p=pLnA, for all A>0, and for all value of p
so y=3^x=exp[Ln(3^x)]=exp(xLn3), let's search the graph of f(x)=exp(xLn3) f is defined in R, and its teminals limits are 0, and + infinity, f' (x) = Ln3.exp(xLn3), it is positif for all value of x, the function is strictly increasing, f(0)=Ln3, please look at the figure 1
the same method with y=2(4.5)^x, we find y=exp[Ln (2(4.5)^x)]=
exp[Ln (2) +Ln(4.5)^x)], because (LnAB=LnA + LnB), so y=2.exp[Ln(4.5)^x)]=2.exp(x[Ln(4.5)]), which domain is R, nd its teminals limits are 0, and + infinity, f' (x)=2.Ln(4.5) exp(x[Ln(4.5)]), which is positif for all value of x, the function is strictly increasing,and then f(0)=2Ln(4.5)
please look the figure 2

marta [7]3 years ago
4 0

shes wrong

1. is graph 3

2. is graph 1

3. 49(1/2) ^1/32x; 42.920kg

4. 5.0

5. 1,710.61

whole quiz



Step-by-step explanation:


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dolphi86 [110]
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Answer:

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