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3 years ago

Help me I need to pass so I can go on to the next thing plz someone help me

Mathematics

1 answer:

Svet_ta [14]3 years ago

3 0

Answer:

Step-by-step explanation:

I dont have the answer but quizlet app or website my daughter is getting all the help and more and its free...... I hope this helps

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Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su

777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

$a, ar, ar^2,...\\a = 7\\r = 7$

$7, 7^2, 7^3, 7^4...$

Sum of n terms in a geometric progression:

$S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}$

For sum of five terms, we put n= 5, a = 7, r = 7

$S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607$

The sum of first five term of GP is 19607.

Verification:

$2801\times 7 = 19607$

Thus, the sum is equal to product of 2801 and 7.

7 0

3 years ago

V= pi r^2h solve for h

Ivenika [448]

Divide each term by πr2 π r 2 and simplify. Divide each term in πr2h=V π r 2 h = V by πr2 π r 2 .

7 0

3 years ago

If f(x) = k where k is a constant, and the points (6,1) and (8,1) lie on the graph of y = f(x), what is the value of f(0)?

Colt1911 [192]

Answer:

The value of f(0)=1

Step-by-step explanation:

We are given that

$f(x)=k$

$y=f(x)$

(6,1) and (8,1) lies on the graph of y=f(x)

We have to find the value of f(0).

$f(6)=1$

$f(8)=1$

$f(x)=k$

By comparing ,we get

k=1

Therefore, $y=f(x)=1$

Now, substitute x=0

$f(0)=1$

Hence, the value of f(0)=1

7 0

3 years ago

Please help me ☺️☺️☺️

MatroZZZ [7]

BT=TD
BD=2*8=16
AB=BD
AB=16

5 0

3 years ago

Solve the equation 3y=2x-3

aev [14]

Answer:

m = 2/3

Step-by-step explanation:

sorry if its wrong

6 0

2 years ago

Help me I need to pass so I can go on to the next thing plz someone help me​

Help me I need to pass so I can go on to the next thing plz someone help me