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Neporo4naja [7]
3 years ago
7

96743 divided by 25 im at school in person so uh ya lol

Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

3,869.72

Step-by-step explanation:

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A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele
Aleksandr-060686 [28]
There are \dbinom62 ways of selecting two of the six blocks at random. The probability that one of them contains an error is

\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13

So X has probability mass function

f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13
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3 years ago
The unit circle edgenunity answers
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Step-by-step explanation:

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3 years ago
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andrezito [222]

angle 5 and angle 4 are exterior angles

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3 years ago
Julie makes $9.26 an hour. this week she worked 20 hours and had $32.62 deducted for her payroll taxes what was her net income
riadik2000 [5.3K]
Net pay $152.58

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8 0
3 years ago
You are dealt one card from a satndard 52-card deck. Find the probability of being dealt an ace or a 7
ruslelena [56]

Answer:

2/13    or  15.38%

Step-by-step explanation:

Number of Aces in a deck = 4

Number of 7s in a deck = 4

Number of cards in a deck = 52

Probability of A or 7 = (4 Aces + 4 Sevens) / 52 cards                                          8 cards / 52 cards

This simplifies to                           2/13    or  15.38%

3 0
2 years ago
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