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weqwewe [10]
4 years ago
14

Solve the inequality. r + 5 < 10

Mathematics
2 answers:
mars1129 [50]4 years ago
7 0
R<5
r has to be less than 5, now doesn't it
alexira [117]4 years ago
4 0
Move 5 to the other side which will be r<10-5. r<5.
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Help! I'll give brainliest to the first correct answer! ​
Mice21 [21]

Answer:A

Step-by-step explanation:

the answer is A

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Simplify (4xz)^2 (xyz)^-1
bixtya [17]
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4 0
3 years ago
How do I solve for a, b and c?
Naya [18.7K]
Firstly expand (x - 3)(ax^2 + bx + c):
ax^3 + bx^2 + cx - 3ax^2 - 3bx - 3c

Now rearrange it so that it's in the form ax^3 + bx^2 + cx + d:
ax^3 + (b-3a)x^2 + (c-3b)x - 3c

Now we can compare both equations:
ax^3 + (b-3a)x^2 + (c-3b)x - 3c = 2x^3 - x^2 - 19x + 12

We get:
(1) a = 2
(2) b - 3a = -1
(3) c - 3b = -19
(4) -3c = 12

If we substitute (1) into (2) we get:
b - 3*2 = -1
b - 6 = -1
b = 5

Now if we solve (4) we get:
-3c = 12
c = -4

Therefor a = 2, b = 5 and c = -4
8 0
3 years ago
7 1/2 divided by 1 1/2 = 5 How to check the answer
Gnom [1K]

Answer:

We verified that the equation 7\frac{1}{2}\div1\frac{1}{2}=5 has both sides equal.

Step-by-step explanation:

We need to solve and verify: 7\frac{1}{2}\div1\frac{1}{2}=5

Solving:

7\frac{1}{2}\div1\frac{1}{2}=5

Converting into improper fractions

\frac{15}{2}\div\frac{3}{2}=5

Converting division sign into multiplication and reversing 3/2 i.e

\frac{15}{2}\times\frac{2}{3}=5

Now simplifying

\frac{15}{3}=5 \\5=5

So, We verified that the equation 7\frac{1}{2}\div1\frac{1}{2}=5 has both sides equal.

7 0
3 years ago
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