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inysia [295]
3 years ago
6

How many tens and ones are in the number 15

Mathematics
1 answer:
nordsb [41]3 years ago
3 0
1 ten and 5 ones :D right?
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Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2
Juli2301 [7.4K]
To find  g (f(x))  you  should  substitute  "4x^2+x+1"   to  "x"  of  g(x)  function. You'll havew:

g(f(x))= (4x^2+x+1)^2-2=\\ \\ =(4x^2+x)^2 +2 \cdot (4x^2+x) \cdot 1 +1^2-2= \\ \\ = 16x^4+8x^3+x^2+8x^2+2x+1-2= \\ \\ = 16x^4+8x^3+9x^2+2x-1

To count (4x^2+x+1)^2  Just  assume  ( [4x^2+x] + 1)^2   and  use the (a+b)^2=a^2+2ab+b^2  formula, where a=4x^2+x  and  b=1
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3 years ago
How to undo the operation and explain why it works a. adding 28 b. dividing by 17
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Read 2 more answers
The normal distribution An automobile battery manufacturer offers a 31/54 warranty on its batteries. The first number in the war
seraphim [82]

Answer:

1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2) a standard deviation of 6.0843 results in a 1.07% replacement rate

3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

based on the given data;

x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months

so

x → N( U = 45, ∝ = 5.6)

Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.

if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery

1) If the manufacturer's assumptions are correct,

p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )

= p( z < -2.5 )

using the standard normal table,

value of z = 0.0062 ≈ 0.62%

so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2)

The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%

so lets say;

p ( x < 31 ) = ( 1.07%) = 0.0107

p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107

now from the standard table

-2.301 is 1.07%

so

( 31 - 45 / ∝ ) = -2.301

-14 / ∝ = -2.301

∝ = -14 / - 2.301

∝ = 6.0843

therefore a standard deviation of 6.0843 results in a 1.07% replacement rate

3)

Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?

p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝]  < [ 54 - 45 / ∝] )

= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝]  < [ 54 - 45 / 6.0843] )

= p ( -2.301 < z < 1.4792 )

= p(Z < 1.5) - p(Z < -2.3)

= 0.9393 - 0.0108

= 0.919 ≈ 91.9%

therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

8 0
3 years ago
José writes this problem:
kramer

Answer:

675÷1600

Step-by-step explanation:

no other one is correct just that one

8 0
3 years ago
the container overflowed because the kids tried to pour in 3 and 3/5 times the amount it would hold. if they tried to pour in 28
ANEK [815]

Answer: 80 Gallons

Explanation:

3 \frac{3}{5} =  3\frac{6}{10}   = 3.6 \\  \frac{288}{3.6}  = 80

8 0
3 years ago
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