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3 years ago

Help me idk what's the answer

Mathematics

2 answers:

jonny [76]3 years ago

5 0

Put them in order:
67,76,76,82,84,87,93
Cross them out side by side,
Then in the middle you get 82 so the median 82 :)

Jobisdone [24]3 years ago

4 0

76, 84, 93, 67, 82, 87, & 76

The mean is just the middle number of the data set,

Start by rewriting the set in order from smallest to biggest:
67, 76, 76, 82, 84, 87, 93

Determine which is the number in the middle,
67, 76, 76, *82*, 84, 87, 93

So, in this case, the median is 82.

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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

$PM^2=(6)^2+(8)^2$

$PM^2=36+64$

$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

3 0

3 years ago

Solve each equation (x+8)(x-2)=-9

Nesterboy [21]

X=1, x=-7 would be the correct answer.

5 0

3 years ago

Read 2 more answers

The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui

mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

$s(t) = -16t^2+v_0t+s_0$

Where,

$s_0$ = initial height of the object,

$v_0$ = initial velocity of the object,

Here,

$s_0=400\text{ feet}$

$v_0=35\text{ feet per sec}$

Hence, the height of the ball after t seconds,

$s(t)=-16t^2+35t+400$

When s(t) = 0,

$\implies -16t^2+35t+400=0$

$t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}$

$t=\frac{-35\pm \sqrt{1225+25600}}{-32}$

$\implies t\approx -4.02\text{ or }t\approx 6.21$

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0

3 years ago

What is the behavior of?

GarryVolchara [31]

Answer:

i thin its option 1 or 2 because by looking at the problem it kinda click after starring at it for awhile

i hope this useful in a way

5 0

3 years ago

Read 2 more answers

Name

Tpy6a [65]

Answer:

1. A container of milk 2L

2. An Eyedropper has 1 mL

3. A cup of punch 250 mL

4. A jar of pickles 500mL

Step-by-step explanation:

Without even measuring, just think of this problem logically. Remember that a 1 L is 1000mL, so it is 1000 times more than 1 mL.

A milk container would hold more than a cup of milk and that is more than 20 mL. The most logical answer would be 2L.

An eyedropper can hold just a little amount of liquid. Just think that it dispenses liquid in drops, the best answer would be 1mL (which is actually an estimate of the volume of a drop is.)

A cup of punch is about 250 mL. The keyword there is a CUP and 25L is a big amount and the cup would have to be HUGE.

Same as above, the keyword there is a jar. A 50L jar would be a very big amount for just a jar of pickles.

8 0

3 years ago