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Svet_ta [14]
3 years ago
11

Help me idk what's the answer

Mathematics
2 answers:
jonny [76]3 years ago
5 0
Put them in order:
67,76,76,82,84,87,93
Cross them out side by side,
Then in the middle you get 82 so the median 82 :)

Jobisdone [24]3 years ago
4 0
76, 84, 93, 67, 82, 87, & 76

The mean is just the middle number of the data set,

Start by rewriting the set in order from smallest to biggest:
67, 76, 76, 82, 84, 87, 93

Determine which is the number in the middle,
67, 76, 76, *82*, 84, 87, 93

So, in this case, the median is 82.
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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
Solve each equation (x+8)(x-2)=-9
Nesterboy [21]
X=1, x=-7 would be the correct answer.
5 0
3 years ago
Read 2 more answers
The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui
mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

s(t) = -16t^2+v_0t+s_0

Where,

s_0 = initial height of the object,

v_0 = initial velocity of the object,

Here,

s_0=400\text{ feet}

v_0=35\text{ feet per sec}

Hence, the height of the ball after t seconds,

s(t)=-16t^2+35t+400

When s(t) = 0,

\implies -16t^2+35t+400=0

t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}

t=\frac{-35\pm \sqrt{1225+25600}}{-32}

\implies t\approx -4.02\text{ or }t\approx 6.21

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0
3 years ago
What is the behavior of?
GarryVolchara [31]

Answer:

i thin its option 1 or 2 because by looking at the problem it kinda click  after starring at it for awhile

i hope this useful in a way  

5 0
3 years ago
Read 2 more answers
Name
Tpy6a [65]

Answer:

1. A container of milk 2L

2. An Eyedropper has 1 mL

3. A cup of punch 250 mL

4. A jar of pickles 500mL

Step-by-step explanation:

Without even measuring, just think of this problem logically. Remember that a 1 L is 1000mL, so it is 1000 times more than 1 mL.

A milk container would hold more than a cup of milk and that is more than 20 mL. The most logical answer would be 2L.

An eyedropper can hold just a little amount of liquid. Just think that it dispenses liquid in drops, the best answer would be 1mL (which is actually an estimate of the volume of a drop is.)

A cup of punch is about 250 mL. The keyword there is a CUP and 25L is a big amount and the cup would have to be HUGE.

Same as above, the keyword there is a jar. A 50L jar would be a very big amount for just a jar of pickles.

8 0
3 years ago
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