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Savatey [412]
4 years ago
10

How many minutes are in 5.5 days

Mathematics
2 answers:
Hatshy [7]4 years ago
7 0
There are 7,920 minutes in 5.5 days

60minutes in an hour
24hours in a day

60 times 24 times 5.5 = 7,920
adell [148]4 years ago
4 0
The answer would be: 7,920


Explanation: This problem is quite simple if you break it down. As long as you know the basics:
24 hours in a day
60 minutes in an hour

If 2x24=48 (the number of hours in two days) and 3x24=72 (the number of hours in three days) then 5.5x24=132 (which must be the number of hours in 5.5 days)

We now know that there are 132 hours in 5.5 days, but we must find the amount of minutes. There is a good formula for this:

(Let "x" be the amount of hours and "y" be the total amount of minutes)

x•60=y
If we substitute x for 132, we are now able to find our total
132•60= 7,920

You now get your answer. To prove this formula works, substitute "x" with "1." You will end up with 60 as your answer, which, as you already know, is this amount of minutes in an hour.


Hope this helps!

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Step-by-step explanation:

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<em>x</em> + a<em>y</em> = b          .......(1)

a<em>x</em> - b<em>y</em> = c        .......(2)

We will use 'Substitution Method' to solve the given system of equations.

In this method, we will find out the value of either of the two variables that is '<em>x</em>' and '<em>y</em>' from one of the two equations in terms of the another variable  and then substitute that value in the other equation to find the value of the another variable.

Now, we will be finding out the value of '<em>x</em>' in terms of '<em>y</em>' from equation (1) and then substitute it in the equation (2).

Consider the equation (1), that is,

   <em>x</em> + a<em>y</em> = b ⇒ <em>x</em> = b - a<em>y</em>          ........(3)

Substitute the value of '<em>x</em>' from (3) in (2), we get

  a(b - a<em>y</em>) - b<em>y</em> = c

⇒ab - a²<em>y</em> - b<em>y</em> = c

⇒-a²<em>y</em> - b<em>y</em> = c - ab

⇒-<em>y</em>(a²+b) = c - ab

⇒<em>y</em>(a²+b) = ab - c

\implies y=\frac{ab-c}{a^{2}+b}

Now, substituting the above value of '<em>y</em>' in equation (3), we get

x=b-a(\frac{ab-c}{a^2+b})

\implies x=\frac{b(a^2+b)-a(ab-c)}{a^2+b}

\implies x=\frac{a^2b+b^2-a^2b+ac}{a^2+b}

\implies x = \frac{b^2+ac}{a^2+b}

Hence, the solution of the given system of equations is,

x = \frac{b^2+ac}{a^2+b} ;\; y = \frac{ab-c}{a^2+b}

5 0
3 years ago
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