They have 23$ and 1$ is needed for when they get in the car. That leaves 22$. It’s 2$ per kilometer so 22/2 is 11.
They can travel 11 kilometers
Moving the number 6 one place to the left would put it where the 3 is, which is the thousands place
So set up the equations
q-12=d
25q+10d=1105
plug in q-12 as d in the second equation:
25q+10q-120=1105, then simplify:
35q=1225
q=35
since there's 12 fewer dimes, we know that there's 23 dimes and 35 quarters.
Answer: does not make sense.
The statement " t<span>he beach ball we played with has a density of 10 grams per cubic centimeter" does not make sense.
Reasoning.
Inflated beach balls have a very low density, they are pretty much only air, plus the weight of the ball per se. Certainly that density is much lower than the density of water.
Inflated beach balls fall slowly in the air because their density is very close to the density of air and float on water because their density is less than the density of water.
Being the density of pure water 1 g/cm^3 you can predict, without any calculation, that the density of the beach ball is less than that and never 10 g/cm^3 which is 10 times the density of pure water.
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Answer: 15 goats
Step-by-step explanation:
h = hens - they have 2 legs
g = goats - they have 4 legs
The equations would be:
h + g = 19
2h + 4g = 68
To solve this, I personally prefer substitution, we're isolating h since we need to find g:
h + g = 19
h = 19 - g
Now that we have h, we can plug this into the second equation:
2h + 4g = 68
2(19 - g) + 4g = 68
38 - 2g + 4g = 68
2g = 30
g = 15
There are 15 goats.
Adding onto this, 19 - 15 = 4, so there are 4 hens.
