All categories

4 years ago

Pls help!! 15 points! What are the minimum and maximum values of t for which |t + 3| ≤ 2?

Mathematics

1 answer:

PSYCHO15rus [73]4 years ago

6 0

Answer:

Minimum: x<-1

Maximum: x> 1

both are also equal to i just don’t have the sign

You might be interested in

The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section

lisabon 2012 [21]

Answer:

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and $y_1(x)=e^{2x}$

To find the $y_2(x)$ we are applying the following formula,

$y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx$

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

$\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx$

$=e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx$

$=e^{2x}\int e^{-4x-4x} \ dx$

$=e^{2x}\int e^{-8x} \ dx$

$=e^{2x}. \frac{e^{-8x}}{-8}$

$=-\frac{e^{-6x}}{8}$

$\therefore y_2(x)=-\frac{e^{-6x}}{8}$

The general solution is

$y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}$

4 0

3 years ago

I need help with this....

trapecia [35]

Answer:

-512

Step-by-step explanation:

The laws of exponents state that multiplying two exponents together of the same base allows you to add the exponents. Raising an exponent to another power allows you to multiply the exponents. In this case. you have $(-2)^3*((-2^3))^2$ . First, you take the second term, or $((-2^3))^2$ and simplify it. Since you're raising an exponent to another exponent you have $(-2)^(3*2)$ , or $(-2)^6$ . Now, you multiply by $(-2)^3$ . Since they both have the same base, you can add the exponents to get $(-2)^9$ . Since $(-2)^9$ is raised to an odd exponent, you know you're answer is going to be negative. $2^9$ is 512, so that negative would be -512. If you're looking for an expression for this, you can write $(-2)^9$

5 0

3 years ago

Which is the value of 3b 2 −b <br> 3b2-b<br> when b = 5?

monitta

<span>I think you mean

3b^2 − b ?

If so you just put in the 5 for b

3*(5)^2 - 5

Do the square first

5^2 = 25

3(25) - 5 =

75 - 5 =

70.

</span>

6 0

4 years ago

Any help? I'm struggling.

Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

a=-7

r=21/-7=-3

$a_{15}=a r^{n-1}=-7(-3)^{15-1}=-7(-3)^{14}=-33480783$

4 0

3 years ago

HELP MATH LAST ONEE!! :D MARKING BRAINLISEST!

OlgaM077 [116]

Answer:

y = -11

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y = mx + b

m - slope

b - y-intercept → (0, b)

We have the slope m = 0 and the point (0, -11) → b = -11.

Substitute:

y = 0x - 11 = -11

It's a horizontal line.

4 0

3 years ago

Read 2 more answers