<h3>
Answer: 7m+30</h3>
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Work Shown:
3(m+2) + 4(6+m)
3m+6 + 24 + 4m
(3m+4m) + (6+24)
7m+30
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Explanation:
In the second step, I used the distribution rule a*(b+c) = a*b+a*c. We multiply the outer term by every term inside. So for instance 3(m+2) = 3*m+3*2 = 3m+6. A similar situation applies to 4(6+m) as well. Afterward, I grouped and combined like terms.
We can think of 3m+4m = 7m as saying "I have 3 maps and someone gave me 4 more maps, so that means I have 3+4 = 7 maps now". The m is a place holder for any number.
Answer:
I would love to help you but were just getting into this subject
Step-by-step explanation:
True. Not sure if this is a true or false question but its true. Have a nice day and blessed be!
Answer:
{ - 33, - 23, 2, 12 }
Step-by-step explanation:
Given
f(x) = 5x - 13 with domain { - 4, - 2, 3, 5 }
To obtain the range substitute the values of x from the domain into f(x)
f(- 4) = 5(- 4) - 13 = - 20 - 13 = - 33
f(- 2) = 5(- 2) - 13 = - 10 - 13 = - 23
f(3) = 5(3) - 13 = 15 - 13 = 2
f(5) = 5(5) - 13 = 25 - 13 = 12
Range is { - 33, - 23, 2, 12 }
Answer:
(1) Not conditional, 5/8
(2) Not conditional, 1/12
(3) Conditional, 1/18
Step-by-step explanation:
Fraction of cars sold
Altima = 1/2
Maxima = 1/3
Sentra = 1 - (1/2 + 1/3) = 1 - 5/6 = (6 - 5)/6 = 1/6
Fraction of cars sold with moon roof
Altima = 3/4 × 1/2 = 3/8
Maxima = 1/2 × 1/3 = 1/6
Sentra = 1/2 × 1/6 = 1/12
(1) Probability (a randomly selected car has a moon roof) = 3/8 + 1/6 + 1/12 = (9+4+2)/24 = 15/24 = 5/8
(2) Probability (a randomly selected car has a moon roof given it is Sentra) = 1/12
(3) Probability (a randomly selected car is a Maxima if it has a moon roof) = 1/3 × 1/6 = 1/18
A conditional probability uses if (as a condition) in making statements or asking questions
An unconditional probability makes statement or ask question without the use of condition (if)