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pantera1 [17]
3 years ago
12

For homework Sarah had seventeen math problems and twenty-eight spelling problems. If she can finish five problems in an hour ho

w long will it take her to finish all the problems
Mathematics
1 answer:
blsea [12.9K]3 years ago
8 0

Answer:

It will take Sarah 9 hours to finish all the the problems.

Step-by-step explanation:

5 problems per hour, 45 total problems. (math + spelling)

45 divided by 5 equals 9

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Please help me for the brainliest answer
7nadin3 [17]
The answer is 928cm. There are 5 sides. When you find the area of a triangle you multiply base times height then divide by two. But in this case there are two identical triangles so you don’t need to divide. 24x12=288. Then you find the area of the long sides. Multiple 25 and 10 and you get 250. There are two of those sides. Now the last thing to do is find the area of the bottom side. For that one you multiply 14 and 10 and get 140. Now you add all of that together and get 928cm.
4 0
4 years ago
Simplify this expression and show all steps:<br> 48m^7/20m^4
Ghella [55]

Answer:

(12/5)m^3

Step-by-step explanation:

It's easier for most of us to write out a fraction / ratio without the " / " symbol:

48m^7

------------

20 m^4

Separate the coefficients from the powers of m:

48     m^7

----- * --------     Now let's reduce each fraction separately:

20      m^4


48/20 = 12/5, and

(m^7) / (m^4) = m^(7-4) = m^3


... so that our final answer is (12/5)m^3.

3 0
3 years ago
Let C = C1 + C2 where C1 is the quarter circle x^2+y^2=4, z=0,from (0,2,0) to (2,0,0), and where C2 is the line segment from (2,
trapecia [35]
Not much can be done without knowing what \mathbf F(x,y,z) is, but at the least we can set up the integral.

First parameterize the pieces of the contour:

C_1:\mathbf r_1(t_1)=(2\sin t_1,2\cos t_1,0)
C_2:\mathbf r_2(t_2)=(1-t_2)(2,0,0)+t_2(3,3,3)=(2+t_2, 3t_2, 3t_2)

where 0\le t_1\le\dfrac\pi2 and 0\le t_2\le1. You have

\mathrm d\mathbf r_1=(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1
\mathrm d\mathbf r_2=(1,3,3)\,\mathrm dt_2

and so the work is given by the integral

\displaystyle\int_C\mathbf F(x,y,z)\cdot\mathrm d\mathbf r
=\displaystyle\int_0^{\pi/2}\mathbf F(2\sin t_1,2\cos t_1,0)\cdot(2\cos t_1,-2\sin t_1,0)\,\mathrm dt_1
{}\displaystyle\,\,\,\,\,\,\,\,+\int_0^1\mathbf F(2+t_2,3t_2,3t_2)\cdot(1,3,3)\,\mathrm dt_2
5 0
3 years ago
Two groups of staff at a store are making flowers to decorate the entrance. If Group A were to do it alone, it would take them 1
Tcecarenko [31]

Answer:

\dfrac{6750}{7}

Step-by-step explanation:

Let x be the number of flowers. If Group A were to make x flowers alone, it would take them 10 hours to complete the task, then they make \dfrac{x}{10} flowers in an hour.  If Group B were to make x flowers alone, it would take them 15 hours to complete the task, then they make \dfrac{x}{15} flowers in an hour.

The groups decided to work together. They can make \dfrac{x}{10}+\dfrac{x}{15}=\dfrac{x}{6} together in an hour and it takes them \dfrac{x}{\frac{x}{6}}=6 hours. Group B took a break for 1 hour and 40 minutes (1\dfrac{2}{3} hour), then Group B works

6-1\dfrac{2}{3}=4\dfrac{1}{3} hours.

Thus,

\dfrac{x}{10}\cdot 6-\dfrac{x}{15}\cdot 4\dfrac{1}{3}=300,\\ \\\dfrac{3x}{5}-\dfrac{13x}{45}=300,\\ \\14x=300\cdot 45=13500,\\ \\x=\dfrac{13500}{14}=\dfrac{6750}{7}.

6 0
3 years ago
The length of a rectangle is 10 yards more than the width. If the perimeter is 68 yards, what are the length and width?
quester [9]

Divide the perimeter by 2, this will give you the sum of one length and one width.

68/2 = 34 yards

Now the length is  10 yards more, so subtract 10 from the 34 and divide by 2 again:

34 - 10 = 24

24 /2 = 12

The width is 12 yards.

The length is 12 + 10 = 22 yards.

5 0
3 years ago
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