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MAVERICK [17]
3 years ago
9

In the diagram below bc is an altitude of abd.to the nearest whole unit.what is the length of cd

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0
Pythagorean theorem:
                       AB = √30^2 + 16^2 = 34

These are similar triangles.

∠BAC is congruent to ∠BAD
∠ACB is congruent with ∠ABD (both right angles)

Using ratios:
               AC / AB = AB / (AC + CD)
             AC + CD =  AB² / AC
                       CD = AB² / AC - AC
                       CD = 34² / 16 - 16               
                       CD = 56.25
The answer to this question is 56.
serg [7]3 years ago
5 0
Solution:
Use the Pythagorean theorem:
AB = √30^2 + 16^2 = 34


Since ∠BAC is congruent to ∠BAD
∠ACB is congruent with ∠AB
Then,
 AC / AB = AB / (AC + CD)
 AC + CD =  AB² / AC
CD = AB² / AC - AC
 CD = 34² / 16 - 16               
 CD = 56.25


So the answer is 56

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QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

{h}^{2}  =  {6}^{2}  +  {8}^{2}

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Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

{l}^{2}  +  {33}^{2}  =  {55}^{2}

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{l}^{2}  = 1936

l =  \sqrt{1936}

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Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the values to get,

d=\sqrt{( - 1-2)^2+(3- - 1)^2}

d=\sqrt{( - 3)^2+(4)^2}

d=\sqrt{9+16}

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d = 5

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QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

d=\sqrt{( - 3-2)^2+( - 3- 2)^2}

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Answer: D

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Step-by-step explanation:

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