Answer:
200g of NaOH
Explanation:
The following data were obtained from the question:
Molar mass of NaOH = 40g/mol
Volume = 500mL
Molarity of NaOH = 10M
Next, we shall determine the number of mole of NaOH present in the solution. This is illustrated below:
Molarity of NaOH = 10M
Volume = 500mL = 500/1000 = 0.5L
Mole of NaOH =...?
Molarity = mole /Volume
10 = mole /0.5
Cross multiply
Mole = 10 x 0.5
Mole of NaOH = 5 moles
Finally, we can convert 5 moles of NaOH to grams. This is illustrated below:
Molar mass of NaOH = 40g/mol
Mole of NaOH = 5 moles
Mass of NaOH =...?
Mole = Mass /Molar Mass
5 = Mass /40
Cross multiply
Mass = 5 x 40
Mass of NaOH = 200g
Therefore, 200g of NaOH is needed to prepare the solution.
Answer:
Explanation:
We can use the Ideal Gas Law and solve for T.
pV = nRT
Data
p = 2.91 atm
V = 78.13 L
n = 3.07 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
Calculations
