Answer:
The percentage is k 
%
Explanation:
From the question we are told that
The mass of the stibnite is 
The volume of KBrO3(aq) is 
The concentration of KBrO3(aq) is 
Now the balanced ionic equation for this reaction is
The number of moles of 
is
substituting values
from the reaction we see that 1 mole of reacts with 3 moles of 
so 0.003325 moles will react with x moles of
Therefore
Now the molar mass of is a constant with a values of 
Generally the mass of is mathematically represented as
substituting values
The percentage of Sb(antimony) in the overall mass of the stibnite is mathematically evaluated as
k 
k %
A. The kitten shivers like she’s cold
those link share ppl are SOOOOOO ANNOYING
Answer:
Freezing point solution = 70.131 °C
Explanation:
Step 1: Data given
Molality = 1.468 molal
A solution is created by dissolving biphenyl (C12H10) into naphthalene
Biphenyl is a non-electrolyte
Freezing point of naphthalene = 80.26 °C
Step 2: Calculate the freezing point depression
ΔT = i*Kf*m
⇒with ΔT = the freezing point depression = TO BE DETERMINED
⇒with i = the van't Hoff factor of biphenyl = 1
⇒with Kf = the freezing point depression constant of naphthalene = 6.90 °C/m
⇒with m = the molality = 1.468 molal
ΔT = 1 * 6.90 °C/m * 1.468 °C
ΔT = 10.13 °C
Step 3: Calculate the freezing point of the solution
ΔT = 10.13 °C
Freezing point solution = freezing point naphthalene - 10.13 °C
Freezing point solution = 80.26 °C - 10.129 °C
Freezing point solution = 70.131 °C
