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3 years ago

5

How many liters of oxygen gas, at standard temperature and pressure, will react with 35.4 grams of calcium metal? Show all of th

e work used to solve this problem. 2Ca + O2 yields 2CaO

1 answer:

maks197457 [2]3 years ago

3 0

9.9 liters is your answer

Hope this helps ;)

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A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M Na

s344n2d4d5 [400]

Answer:

a: before equivalence point

b: equivalence point

c: before equivalence point

d: after the eqivalence point

e: before equivalence point

f: after the eqivalence point

Explanation:

Balanced equation of reaction:

NaOH +HCl =NaCl +H2O;

Volume of HCl is fixed and it 100ml and concentration is 1.0M

N1 and N2 normality of HCl and NaOH respectively;

V1 and V2 volume of HCl and NaOH respectively;

we have given molarity but we need normality;

$Normality=molarity \times n-factor$

<em>but in case of NaOH and HCl n-factor is 1 for each.</em>

hence

normality=molarity;

At equivalence point: $N_1V_1=N_2V_2$

Before equivalence point : $N_1V_1>N_2V_2$

After the equivalence point: $N_1V_1$

$N_1V_1=100\times1=100$

case a: 5.00 mL of 1.00 M NaOH

$N_2V_2=5\times1=5$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case b: 100mL of 1.00 M NaOH

$N_2V_2=100\times1=100$

$N_1V_1=N_2V_2$ hence it is equivalence point

case c: 10.0 mL of 1.00 M NaOH

$N_2V_2=10\times1=10$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case d: 150 mL of 1.00 M NaOH

$N_2V_2=150\times1=150$

$N_1V_1$ hence it is after the eqivalence point

case e: 50.0 mL of 1.00 M NaOH

$N_2V_2=50\times1=50$

$N_1V_1>N_2V_2$ hence it is before equivalence point

case f: 200 mL of 1.00 M NaOH

$N_2V_2=200\times1=200$

$N_1V_1$ hence it is after the eqivalence point

7 0

3 years ago

The three most common states of matter on Earth are solids,blank

Nostrana [21]

Answer:

<h3>example:</h3><h3>meaning of the blank you need to do complete the words</h3>

Explanation:

<h2>#CarryOnLearning</h2>

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3 years ago

1-<br> the<br> Nalt and Gil-<br> Cu2+<br> ad out- <br> what are the spectator ions in this reaction

Mrac [35]

Answer:

cu2 is 5he correct answer

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1 year ago

Question 7-Which of the following is not an acid-base neutralization reaction?

docker41 [41]

Answer:- It is choice D. $H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4$

Explanations:- In general, a neutralization reaction is the reaction of an acid with base to form salt and water.

in first reaction the reaction is taking place between ammonia(a base) and hydrochloric acid(an acid) to form their salt(ammonium chloride). So, it is an acid-base neutralization reaction.

In second reaction, sodium hydroxide(a base) is reacting with acetic acid(an acid) to form their salt(sodium acetate) and water. So, it is an acid-base neutralization reaction.

In third reaction, Nitric acid is reacting with calcium hydroxide(a base) to form a salt(calcium nitrate) and water. So, it is an acid-base neutralization reaction.

In fourth reaction, sulfuruc acid is reacting a sodium chloride(a salt) to give a double replacement reaction. It is not an acid-base neutralization reaction as it's not taking place between an acid and base.

So, the correct choice is D. $H_2SO_4+2NaCl\rightarrow 2HCl+Na_2SO_4$

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3 years ago

Read 2 more answers

melamori03 [73]

The driving thrust of the car produced by the engine is the main forward force.

The main opposing forces are air resistance (from the wind) and friction (between the tyres and the road)

Since the air resistance + friction = driving force the car moves at a constant speed.

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2 years ago