2 years ago

Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz need help due

Mathematics

1 answer:

ololo11 [35]2 years ago

7 0

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Question 6

olga nikolaevna [1]

The answer to your question: 5 - 6t
why it’s saying for each number for 6 so what ever number times 6 is t

6 0

2 years ago

Simplify x+2/x^2+2x-3 divide by x+2/x^2-x

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

2 years ago

The area of the city of Vancouver is 115 km^2. if the shape of Vancouver is approximately a square, how wide is the city of Vanc

Dmitry [639]

Answer:

The wide of the city is 10.7km

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of a square

a = area = 115 km²

s = side

a = s * s

now we replace with the known values

115 km² = s * s

115 km² = s²

√(115 km²) = s

10.724km = s

Round to the nearest tenth

s = 10.724km = 10.7km

The wide of the city is 10.7km

5 0

2 years ago

Easy and I Will mark Brainliest

sladkih [1.3K]

Answer:

Ty What Do i Do Tho And Btw Ty For The Brainliest If You Give Me Some Have A Nice Rest Of Your Day. From: Destiny To: You ....

Step-by-step explanation:

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2 years ago

Can the sine rule relationship in trigonometry be used with non right angled triangle?

vaieri [72.5K]

Answer:

Yes

Step-by-step explanation:

The sine rule works on all triangles (not just right-angled triangles) where a side and it's opposit angles are known.

4 0

2 years ago