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kodGreya [7K]
3 years ago
9

Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz need help due

Mathematics
1 answer:
ololo11 [35]3 years ago
7 0
What do you need help with ...?
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A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he
Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

h(t) = -16t^2 + 30t

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

f(x) = ax^2 + bx + c:

f(\frac{-b}{2a}) = maximum/minimum

i.e we first solve for \frac{-b}{2a}

Then substitute \frac{-b}{2a} for x in f(x) = ax^2 + bx + c

In our case:

First we need to solve \frac{-b}{2a}

Then substitute \frac{-b}{2a} for t in h(t) = -16t^2 + 30t

By comparison:

b = 30

c = -16

\frac{-b}{2a} = \frac{-30}{2 * -16}

\frac{-b}{2a} = \frac{-30}{-32}

\frac{-b}{2a} = \frac{30}{32}

\frac{-b}{2a} = \frac{15}{16}

Substitute \frac{15}{16} for t in h(t) = -16t^2 + 30t

h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})

h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}

h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}

h(\frac{15}{16}) = \frac{-225 + 450}{16}

h(\frac{15}{16}) = \frac{225}{16}

h(\frac{15}{16}) = 14.0625

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because 14.0625 < 15

8 0
2 years ago
Sandi is 13 years old. Karla is 3 times Sandi's age. How old is Karla?
RoseWind [281]
39. 13x3.....................

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3 years ago
Help me please! :)<br> ㏒(4x)=2
Ray Of Light [21]
Answer: x=25 work below :)

4 0
3 years ago
Can you please help???
marusya05 [52]

Answer:

2 or 3 I think

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5 0
2 years ago
Help a brother out!!
zhenek [66]

Answer:

B,D,E for sure

Step-by-step explanation:

Not A because a parabola looks different. Not sure about C.

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