Question

Lincoln middle school plans to collect more than 2,000 cans of food in a food drive. So far, 668 cans have been collected. WRITE AN INEQUALITY to find numbers of cans the school can collect on each of the final 7 days of the drive to meet this goal. IDENTIFY WHAT YOUR VARIABLE REPRESNTS.

Answer 1

Let x be the unknown number.

7x + 668 < 2000     => 7x plus 668 is less than 2000

where:
7x => x represents the number of cans to be collected in 7 days
668 is the number of cans already collected.
2000 is the target number of cans.

7x  +  668    <    2000
        - 668           -668
7x                <   1332
÷7                        ÷7
x                  <    190.30
or
x < 190

To check:

7x + 668 < 2000
7(190) + 668 < 2000
1330 + 668 < 2000
1998 < 2000

Answer 2

Answer:

$7x+668>2000$

Step-by-step explanation:

Given:

Lincoln middle school plans to collect more than 2,000 cans of food

They have already collected 668 cans

To Find:  WRITE AN INEQUALITY to find numbers of cans the school can collect on each of the final 7 days of the drive to meet this goal.

Solution :

Let x be the number of cans collected on each day.

Cans collected on 7 days = 7x

Since they already collected 668 cans

So they have total cans = 7x+668

We are given that they are required to collect more than 2000 cans

⇒$7x+668>2000$

Thus this is the required inequality to find the numbers of cans collect on each final 7 days of drive

Now, $7x+668>2000$

⇒ $7x>2000-668$

⇒ $7x>1332$

⇒ $x>\frac{1332}{7}$

⇒ $x>190.28$

Thus they require to collect more than approx. 191 cans each day