F(x) = 5(-3x) ^2 - (-3x) + 1
f(x) = -8x ^2 + 3x + 1
f(x) = -8x ^3 + 3x
Step-by-step explanation:
you must have made a typo here.
none of the answer options are correct for the given problem.
let me just show you what you told me, and how I can solve at least this :
2a/4 = b/4
this simply means (multiply both sides by 4) :
2a = b
so, 5b is then (multiplying both sides by 5) :
5×2a = 5b
10a = 5b
but again, "10a" is not among the offered answers.
so, I don't know if you made a mistake with the basic problem or with the answer options.
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
The rules for multiplying powers with the same base is you are basically doing the pemdas method Please Excuse My Dear Aunt Sally pemdas
As x approaches 5
hmm, we can divide the (x-5) from top and bottom to get x-5
if we input 5 for x we get
5-5=0
it approaches 0 as x approaches 5
