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3 years ago

Find f(f(x))? Thanks so much!

Mathematics

2 answers:

Bess [88]3 years ago

8 0

The answer is
f(-3x^2+3x)=-27x^4

scZoUnD [109]3 years ago

5 0

Answer is -27x^4
Hope this helps
Have a great day or night

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Find the greatest common factor of 12m^2 and 9b^4

mylen [45]

Answer:

The greatest common factor of 12m^2 and 9b^4 is 3.

I hope this could help, let me know if you need anymore help.

8 0

3 years ago

How do you solve for LMN? I keep getting 15

Marina86 [1]

Answer:

60°

Step-by-step explanation:

90° = 6x

15° = x

60° = 4x

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2 years ago

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Which triangles are congruent? How do you know?

choli [55]

Use the side lengths! C and D have lengths of 3 and heights of 4.
Also use how far away they are from the axis.

Both C and D are 2 away from each axis on the end point.
This also goes with A.
However, B does not seem to be congruent in the sense of (coordinates)
It is the same length and height.

3 0

3 years ago

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What is the value of x?<br><br> Enter your answer, as a decimal, in the box.

Katarina [22]

Answer:

$x=50.6cm$

Step-by-step explanation:

Triangle MAB is similar to triangle MNP

Since the triangles are similar, the corresponding ratios are in the same proportion.

Therefore we can write the relation;

$\frac{|MB|}{|MP|}=\frac{|MA|}{|MN|}$

$\frac{x}{72.6}=\frac{46.2-14}{46.2}$

This implies that;

$\frac{x}{72.6}=\frac{32.2}{46.2}$

We multiply both sides by 72.6 to get

$\frac{x}{72.6}\times 72.6=\frac{32.2}{46.2}\times72.6$

$\Rightarrow x=50.6$

Hence the value of $x$ is 50.6 cm

8 0

3 years ago

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All vectors are in Rn. Check the true statements below:

Oduvanchick [21]

Answer:

A), B) and D) are true

Step-by-step explanation:

A) We can prove it as follows:

$Proy_{cv}y=\frac{(y\cdot cv)}{||cv||^2}cv=\frac{c(y\cdot v)}{c^2||v||^2}cv=\frac{(y\cdot v)}{||v||^2}v=Proy_{v}y$

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that $||Ax||=\sqrt{(A_1 x)^2+\cdots (A_n x)^2}$ . Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then $||Ax||=\sqrt{(x_1)^2+\cdots (x_n)^2}=||x||$ .

C) Consider $S=\{(0,2),(2,0)\}\subseteq \mathbb{R}^2$ . This set is orthogonal because $(0,2)\cdot(2,0)=0(2)+2(0)=0$ , but S is not orthonormal because the norm of (0,2) is 2≠1.

D) Let A be an orthogonal matrix in $\mathbb{R}^n$ . Then the columns of A form an orthonormal set. We have that $A^{-1}=A^t$ . To see this, note than the component $b_{ij}$ of the product $A^t A$ is the dot product of the i-th row of $A^t$ and the jth row of $A$ . But the i-th row of $A^t$ is equal to the i-th column of $A$ . If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then $A^t A=I$

E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.

In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set $\{u_1,u_2\cdots u_p\}$ and suppose that there are coefficients a_i such that $a_1u_1+a_2u_2\cdots a_nu_n=0$ . For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then $a_i||u_i||=0$ then $a_i=0$ .

5 0

3 years ago