Perimeter=2L+2W
L=W+5, substitute in place of 2L
90=2(W+5)+2W
90=2W+10+2W
90-10=4W
80=4W
80/4=W
W=20, if width is 20 than the length is 20+5=25 cm
Answer:
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So it’s saying that the following set in roster form: (1) N = (x :x is an odd number, 21< × ≤ 35,×€ N)?
It seems to be that the Roster form would do not do anything but the thing is that this listing would give us the output of a set from this problem.
Your answer would be, N = Set of Odd Numbers such that x is greater than 21 and less than or equal to 35 = {23, 25, 27, 29, 31, 33, 35}.
The last one is wrong because a triangle is a paralellogram and not a quadrilateral. Please mark as brainliest. :)
Answer:
20 measured and 10 used
Step-by-step explanation:
Total number of participants is given as n = 10.
Number of treatment conditions = 2
Total measurements is therefore 2 × 10 = 20
Therefore, in total, 20 scores will be measured in the given study.
Now there are two samples and for each sample, for each sample we need to calculate the mean = Sum of value(measures)/Number of measures
mean = Sum of value(measures)/10
Therefore, we are going to have 20 measured and 10 used to calculate the sample mean and the sample variance.