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Musya8 [376]
3 years ago
6

Solve for x. 3.rº 80° 20° A. 10 B. 20 C. 50 D. 80

Mathematics
2 answers:
ohaa [14]3 years ago
6 0

Answer:

x = 20°

Step-by-step explanation:

The angle measures should add up to 180 degrees. So that leaves us with 100 degrees left to find if we take out the 80 given.

3x + 2x simplifies to 5x. 5x must equal 100.

100/5 = 20.

Therefore x = 20.

Lesechka [4]3 years ago
4 0
B:20

Hope this helps!
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A number increased by 24 is 112. what is the number
dexar [7]
I believe the correct number is 88.
8 0
3 years ago
Jason has $800 more than Paul. Alex has $150 less than Jason. How much more does Alex have than Paul?
jolli1 [7]

Hey there!!

Jason = 800 + Paul

Alex = Jason - 150

How much more does Alex have the Paul?

Let's take the equation of Alex

... Alex = Jason - 150

... Add 150 on both sides

... Alex + 150 = Jason

Now we have the equation for Jason,

... Jason = 800 + Paul , and we got Alex + 150 = Jason

... Now let's plug in the values

... Alex + 150 = 800 + Paul

Subtract 150 on both sides...

Alex = 800 - 150 + Paul

... Alex = 650 + Paul

Now we got the answer for our question :

The answer - Alex has $650 than Paul.

Hope my answer helps!!


4 0
3 years ago
What is the simplified form of the expression? HELP ASAP
galina1969 [7]

Answer:

360

Step-by-step explanation:

\frac{5(14 - 2)^{2} }{2}  =  \frac{5 {(12)}^{2} }{2}  =  \frac{5(144)}{2} \\  \\  \frac{720}{2}   = 360

6 0
3 years ago
Read 2 more answers
Answer QUICK!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Vaselesa [24]

Answer:

half of a number is 15

Step-by-step explanation:

An equation must contain an equality sign.

The third option is the only phrase that can be represented as an equation: \frac{x}{2}=15

8 0
3 years ago
The following data represent the pulse rates? (beats per? minute) of nine students enrolled in a statistics course. Treat the ni
charle [14.2K]

Answer:

(a)77.4bpm

(b)Mean of Sample 1 = 70.3 beats per minute.  

Mean pulse of sample 2 = 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.

Step-by-step explanation:

(a)Population mean pulse.

The pulse of the nine students which represent the population are:

  • Perpectual Bempah      64
  • Megan Brooks               77
  • Jeff Honeycutt               89
  • Clarice Jefferson           69
  • Crystal Kurtenbach       89
  • Janette Lantka              65
  • Kevin McCarthy             88
  • Tammy Ohm                  69
  • Kathy Wojdya                 87

\text{Population Mean} =\dfrac{64+77+89+69+89+65+88+69+87}{9} \\=\dfrac{697}{9} \\\\=77.44

The population mean pulse is approximately 77.4 beats per minute.

(b)Sample 1: {Janette,Clarice,Megan}

  • Janette: 65bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 1

\text{Sample 1 Mean} =\dfrac{65+69+77}{3} \\=\dfrac{211}{3} \\\\=70.3

Sample 2: {Janette,Clarice,Megan}

  • Perpetual: 64bpm
  • Clarice: 69bpm
  • Megan: 77bpm

Mean of Sample 2

\text{Sample 2 Mean} =\dfrac{64+69+77}{3} \\=\dfrac{210}{3} \\\\=70

The mean pulse of sample 1 is approximately 70.3 beats per minute.  

The mean pulse of sample 2 is approximately 70 beats per minute.

(c)

  • The mean pulse rate of sample 1 underestimates the population mean.
  • The mean pulse rate of sample 2 underestimates the population mean.
7 0
3 years ago
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