(0,5)(3,-1)
slope = (-1 - 5) / (3 - 0) = -6/3 = -2
y = mx + b
slope(m) = -2
(use either of ur points...(0,5)...x = 0 and y = 5
now we sub and find b, the y int
5 = -2(0) + b
5 = b
so ur line is : y = -2x + 5
For each <em>x</em> in the interval 0 ≤ <em>x</em> ≤ 5, the shell at that point has
• radius = 5 - <em>x</em>, which is the distance from <em>x</em> to <em>x</em> = 5
• height = <em>x</em> ² + 2
• thickness = d<em>x</em>
and hence contributes a volume of 2<em>π</em> (5 - <em>x</em>) (<em>x</em> ² + 2) d<em>x</em>.
Taking infinitely many of these shells and summing their volumes (i.e. integrating) gives the volume of the region:
![\displaystyle 2\pi \int_0^5 (5-x)(x^2+2)\,\mathrm dx=2\pi\int_0^5 (10-2x+5x^2-x^3)\,\mathrm dx=\boxed{\frac{925\pi}6}](https://tex.z-dn.net/?f=%5Cdisplaystyle%202%5Cpi%20%5Cint_0%5E5%20%285-x%29%28x%5E2%2B2%29%5C%2C%5Cmathrm%20dx%3D2%5Cpi%5Cint_0%5E5%20%2810-2x%2B5x%5E2-x%5E3%29%5C%2C%5Cmathrm%20dx%3D%5Cboxed%7B%5Cfrac%7B925%5Cpi%7D6%7D)
The object reaches the lowest height at 5 seconds
<h3>How to determine the time?</h3>
The function is given as:
f(t) = -2t² +22t + 6
Differentiate the function
f'(t) = -4t +22
Set to 0
-4t +22 = 0
Subtract 22 from both sides
-4t = -22
Divide both sides by -4
t = 5.5
Remove decimal points
t = 5
Hence, the object reaches the lowest height at 5 seconds
Read more about quadratic functions at:
brainly.com/question/1214333
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Answer:
Yes they do!
Step-by-step explanation:
Both fractions simplify into approximately 0.68
Hope this helps!
Answer:
Which measure?
Step-by-step explanation: