Answer:
C
Step-by-step explanation:
Given
![\sqrt[4]{81y^{12} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B81y%5E%7B12%7D%20%7D)
= ![\sqrt[4]{3^{4} }](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B3%5E%7B4%7D%20%7D)
= 3y³ → C
Answer:
D
Step-by-step explanation:
If you add 0 to anything, you do not have anything new when you are finished. A is an identity.
When you multiply 1 times anything, you do not get anything new. B is an identity
When you switch the order of two numbers and they are not affected by signs, then you are using the commutative property of addition. Nothing changes. C is an identity.
D is the problem child. Nothing I can think of right now will not change will you add 1 to it. If you can think of something that doesn't change when you add one to it, please put it in the comments. Otherwise, D is not an identity.
Center A : 375 per yr
Center B : 35 + 12(12) + 5(52) = 35 + 144 + 260 = 439 per yr
I multiplied 12 * 12 because it was $ 12 a month and there are 12 months in a yr. I multiplied 5 * 52 because each aerobic class is $ 5 per class, and she went once per week, and there are 52 weeks in a yr.
so the cheaper one is Center A
Answer:
5
Step-by-step explanation:
The square root of a number is basically that number multiplied by itself.
for example, the square root of 4 is 2 because 2 x 2 is 4
the square root of 25 is 5 because 5 x 5 = 25
<u><em> . . five and one hundred four thousandths</em></u>
