Are the two cylinders similar? The diagrams are not drawn to scale.

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

Answer:

a) no

Step-by-step explanation:

-The diagrams can be said to be mathematically similar if the dimensions of their corresponding sides enlarge or reduce by the same factor.

-We therefore determine the enlargement factor for both the radius and height as below:

-Let k be the scale factor

$k_r=\frac{R}{r}\\\\=\frac{3.64}{2.6}\\\\=1.4\\\\k_h=\frac{H}{h}\\\\=\frac{10.192}{8.32}\\\\=1.225\\\\k_r\neq k_h$

Hence, the cylinders are not mathematically similar since the enlargment factors for the radius and height are not equal.

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step-by-step explanation:

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salantis [7]

Answer:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: