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2 years ago

Are the two cylinders similar? The diagrams are not drawn to scale.

Mathematics

1 answer:

vovangra [49]2 years ago

5 0

Answer:

a) no

Step-by-step explanation:

-The diagrams can be said to be mathematically similar if the dimensions of their corresponding sides enlarge or reduce by the same factor.

-We therefore determine the enlargement factor for both the radius and height as below:

-Let k be the scale factor

$k_r=\frac{R}{r}\\\\=\frac{3.64}{2.6}\\\\=1.4\\\\k_h=\frac{H}{h}\\\\=\frac{10.192}{8.32}\\\\=1.225\\\\k_r\neq k_h$

Hence, the cylinders are not mathematically similar since the enlargment factors for the radius and height are not equal.

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Solve n x 8 = 24 please help me and solve the equation.

zaharov [31]

Answer:

Step-by-step explanation:

Set it up as

8n = 24

n = 24/8

n = 3

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A restaurant serves custom-made omelets, where guests select meat, cheese, and vegetables to be added to their omelet. There are

FrozenT [24]

Answer:

15 possible combinations

Step-by-step explanation:

Given

$Vegetables = 6$

$Selection = 2$

Required

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The question emphasizes on "selection" which means "combination".

So; To answer this question, we apply the following combination formula:

$^nC_r = \frac{n!}{(n-r)r!}$

In this case:

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$^6C_2 = \frac{6!}{4!2!}$

$^6C_2 = \frac{6*5*4!}{4!2*1}$

$^6C_2 = \frac{6*5}{2}$

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2 years ago

3 log 2x=4 Please solve

Leno4ka [110]

$3 log 2x=4\ /:3\\log2x=\frac{4}{3}\\10^{\frac{4}{3}}=2x\ /:2\\x=\frac{10\sqrt[3]{10} }{2}\\x=5\sqrt[3]{10}$

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2 years ago

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Svetach [21]

Answer:

$9\sqrt{3}$

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yawa3891 [41]

Step-by-step explanation:

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• Finding coordinates of Equⁿ (i) :-

Step 1 : Put x = 0 :-

$\tt y = 2x = 2(0) = \red{0}$

Step 2: Put x = 1 :-

$\tt y = 2x = 2(1) = \red{2}$

$\boxed{\begin{array}{c|c|c} \bf x & \tt 0 &\tt 1 \\ \bf y &\tt 0 & \tt 2 \end{array}}$

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• Finding coordinates of equⁿ (ii) :-

Step 1 : Put x = 0 :-

$\tt y = x + 1 = 1 + 0 = \red{1}$

Step 2: Put x = 1 :-

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Now plot these points on the graph Taking appropriate scale . Refer to the attachment in graph . From graph the Solution is (1,2) .

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