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4 years ago

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A farmer has a sack of grain, a chicken and a fox. He has to get them across the river and he can't go around or fly but he does

have a boat. He can only take one thing at a time across the river. How can he get them across?

1 answer:

snow_tiger [21]4 years ago

7 0

<span>

</span><span>http://www.squiglysplayhouse.com/BrainTeasers/bt.php?id=119
this should help</span>

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A bag contains five red marbles and three green marbles.

Tatiana [17]

1.3/8 because there is a total of 8 marbles but only 3 of them are green.
2. A 52 deck of cards has 4 or each card not including the Jokers so it would be 4/52.
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6.&7. coins aren't my cup of tea all i can say is maybe google it :P
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3 years ago

How do I find b in y=mx+b?

Ainat [17]

Answer:

In the equation y = mx + b for a straight line, the number m is called the slope of the line. Let x = 0, then y = m • 0 + b, so y = b. The number b is the coordinate on the y-axis where the graph crosses the y-axis.

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3 years ago

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What is 90 divided by 12???? <br> pls help i need to get my grades up

Andrew [12]

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7.5

Step-by-step explanation:

cant u just g oogle it?

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3 years ago

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Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview

svetlana [45]

Answer: The required solution is

$y=(-2+t)e^{-5t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.$

So, the general solution of the given equation is

$y(t)=(A+Bt)e^{-5t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.$

According to the given conditions, we have

$y(0)=-2\\\\\Rightarrow A=-2$

and

$y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.$

Thus, the required solution is

$y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.$

6 0

3 years ago

Jared has 12 more comic books than Zoe. If they have 28 comic books

ZanzabumX [31]

Answer:

20 comic books

Step-by-step explanation:

Let us first <u>set up a variable</u>, x, for the number of books that Zoe has. If Jared has 12 more comics than Zoe, he would have x+12 books.

Given that Zoe and Jared have a total of 28 comic books, let us write an <u>equation</u> and solve for x:

$x+x+12=28\\2x+12=28$

Now that we have a <u>simplified</u> version of the equation, let us solve for x by <u>isolating the variable</u> on the left side:

$2x=28-12\\2x=16\\x=8$

We now know that x=8, and also that Jared has x+12 books. To find the number of comic books Jared has, let us <u>add</u> 12 to x:

$x+12=\\8+12=\\20\\$

Therefore, Jared has 20 comic books.

<em>I hope this helps! Please let me know if you have any further questions :)</em>

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3 years ago