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marissa [1.9K]
3 years ago
14

When a graph has points (-5,2) what is the zero of the function

Mathematics
1 answer:
Ghella [55]3 years ago
7 0
I almost 100 percent sure it’s 3
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PLEASE FIND THE VERTEX AND IF IT OPENS UP OR DOWN ON A GRAPH!
Margaret [11]

Answer:

There's no negative sign in front of the absolute value so it opens upward. As for the vertex, the x value will be whatever makes what is in the absolute value symbols 0 which is 2.5 in our case and the y-coordinate is 3 so the vertex is (2.5, 3).

3 0
3 years ago
Find the circumferences of the two circles. Circle A has a radius of 21 meters and Circle B has a radius of 28 meters. Use penci
eimsori [14]

Answer:

1.) Circumference of circle A = 131.95 metre

2.) Circumference of circle B = 175.93 metre

3.) Yes. Radius is proportional to the circumference.

Step-by-step explanation: Given that Circle A has a radius of 21 meters and Circle B has a radius of 28 meters

Circumference of a circle = 2πr

For circle A

Radius r = 21

Circumference = 2 × 3.143 × 21

Circumference = 131.95 metre

For circle B

Circumference = 2 × 3.143 × 28

Circumference = 175.93 metre

Is the relationship between the radius of a circle and the distance around the circle the same for all​ circles? YES

Because the radius of the circle is proportional to the distance around them ( circumference ) for all the circle. That is, the larger the radius, the larger the circumference

6 0
3 years ago
the figures above are similar. Find the missing length . show your work. 1. is 5" x 3" the other is 3" by ?
Oxana [17]
If one is 5"x3", and the other having the same orientation is 3"x?, then
by similar figures, 
5/3=3/x
cross multiply,
5x=3*3
x=9/5=1.8"

With the original figure, it is possible to validate the above answer.
8 0
4 years ago
(X^3+1)dividend (x-1)
bazaltina [42]

x^3=x\cdot x^2 and x^2(x-1)=x^3-x^2. So we have a remainder of

(x^3+1)-(x^3-x^2)=x^2+1

x^2=x\cdot x and x(x-1)=x^2-x. Subtracting this from the previous remainder gives a new remainder

(x^2+1)-(x^2-x)=x+1

x=x\cdot1 and 1(x-1)=x-1. Subtracting this from the previous remainder gives a new one of

(x+1)-(x-1)=2

and we're done since 2 does not divide x. So we have

\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}

4 0
3 years ago
Can any two Isosceles triangles always be SIMILAR to each other ? <br><br> true or false
wlad13 [49]
False it is not similar same thing
5 0
3 years ago
Read 2 more answers
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