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iris [78.8K]
3 years ago
14

If 4 adult elephants eat 320 pounds of food, how many ounces of food should the zookeeper purchase?

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Answer:

Step-by-step explanation:

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A circle has its center at the center of a square with 26-inch sides. Using 3.14 for pi, find the area of the square not covered
AlladinOne [14]
For squrae
area=side²
perimiter=4(side)

for circle
area=pir²
circumference=2pir

side=diameter, diameter/2=radius=side/2


find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches

areanotcovered=676-530.66=145.34 square inches not coverd


ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785

7 0
2 years ago
Read 2 more answers
{(12*3)+6}-3^2 divided by (9-6)
Mrac [35]
33. 12*3=36 the u add 6 so it becomes 42. 3^2 is 9 so if u subtract 9 from 42 it becomes 33. 
6 0
3 years ago
Find the center of the equation 4x2 + y2 + 8x-5= 0.
evablogger [386]

Answer:

(-1,0)

Step-by-step explanation:

Plug it into desmos graphing calculator exactly how it is.

3 0
3 years ago
The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i
hram777 [196]
In mathematics, number sequencing of the same pattern are called progression. There are three types of progression: arithmetic, harmonic and geometric. The pattern in arithmetic is called common difference, while the pattern in geometric is called common ratio. Harmonic progression is just the reciprocal of the arithmetic sequence.

The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to

S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:

S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78


6 0
3 years ago
Write down a differential equation of the form dy/dt = ay + b whose solutions have the required behavior as t → ∞. all other sol
nordsb [41]

The ODE has an equilibrium point at

\dfrac{\mathrm dy}{\mathrm dt}=ay+b=0\implies y=-\dfrac ba

We want y=2 to be an unstable equilibrium solution - in other words, we want all solutions with initial condition y(t_0)=c for c near 2 to diverge from y=2 - so -dfrac ba=2.

Divergence from y=2 would require that for y>2, any solution is increasing, and for y, and solution is decreasing. In order for that to happen, we need

\dfrac{\mathrm dy}{\mathrm dt}=ay+b>0\implies y>-\dfrac ba

if y>2, and

\dfrac{\mathrm dy}{\mathrm dt}=ay+b

if y.

Now we just pick a,b to satisfy these conditions. An easy choice is a=1, which forces b=-2, so that one possible ODE would be

\dfrac{\mathrm dy}{\mathrm dt}=y-2

I've attached a plot of the slope field to demonstrate the behavior of the solutions.

6 0
2 years ago
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