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iris [78.8K]
3 years ago
14

If 4 adult elephants eat 320 pounds of food, how many ounces of food should the zookeeper purchase?

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Answer:

Step-by-step explanation:

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A waiter's weekly salary can be modeled by the equation y = 0.2x + 300, where x is the amount spent by the customers in dollars
butalik [34]

Answer:

A. $100

Step-by-step explanation:

y = 0.2x +300

0.2(500) + 300 = 400

0.2(1000) + 300 = 500

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2 years ago
What is the y intercept of the line
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The y-intercept of this line is 1.

Step-by-step explanation:

We are looking for the y-value when x=0. And that value is 1

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3 years ago
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The height in feet of a water rocket launched from the ground is given by the function h(t) = -16t^2 + 96t where t represents th
Mazyrski [523]
<span>The biggest height is 144 ft at t = 3 seconds.</span>
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3 years ago
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A violin student records the number of hours she spends practicing during each of nine consecutive weeks: 6.2 5.0 4.3 7.4 5.8 7.
spin [16.1K]

Answer:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

Step-by-step explanation:

Assuming this complete question: A violin student records the number of hours she spends practicing during each of nine consecutive weeks:

6.2 5.0 4.3 7.4 5.8 7.2 8.4 1.2 6.3

For this case we need to sort the data first on increasing way and we got:

1.2, 4.3, 5.0, 5.8, 6.2, 6.3, 7.2, 7.4, 8.4

For this case we have 9 values the median would be on the 5 position:

Median = 6.2

The first quartile would be 5 since we analyze 1.2, 4.3, 5.0, 5.8, 6.2 and the middle point is 5.0

The third quartile would be 7.2 since we analyze 6.2, 6.3, 7.2, 7.4, 8.4 and the middle point is 7.2

Then the interquartile rnage would be:

IQR = Q_3 -Q_1= 7.2-5=2.2

And 1.5 IQR = 1.5*2.2=3.3

The lower limit on this case would be:

LL= Q_1 -1.5 IQR= 5-3.3=1.7

And our value is 1.2 is lower than the lower limit 1.7

Considering the smallest data value (1.2) and using the 1.5 × IQR rule, we would:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

B) not classify the value 1.2 as an outlier, because it is not more than 1.5 × IQR below  the first quartile.

False 1.2 is more than 1.5 IQR below the first quartile

C) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  median.

False, we analyze if is an outlier comparing with the Q1 or Q3 not with the median

D) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  mean.

False we analyze if is an outlier comparing with the Q1 or Q3 not with the mean

5 0
3 years ago
The sequence follows a minus 3 pattern: 12, 9, 6, 3, ....
hram777 [196]
X times -3= a
i think thats it
3 0
3 years ago
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