All categories

2 years ago

In parallelogram HJKL if HM=12 find HK. K M M H L

Mathematics

1 answer:

Anestetic [448]2 years ago

7 0

Answer:

HK = 24

Step-by-step explanation:

HK and JL are diagonals of the parallelogram.

Recall that diagonals of a parallelogram bisect each other. This implies that, they divide each other into equal parts.

Therefore,

HK = 2(HM)

HM = 12

Thus,

HK = 2(12)

HK = 24

You might be interested in

Estimate 324,867 to the nearest whole number

jenyasd209 [6]

300,000 тнaт ιѕ мy anѕwer and all yoυ нave тo do ιѕ looĸ aт тнe ѕecond nυмвer 4 or leѕѕ leт ιт reѕт 5 or мore gιve ιт a score

8 0

3 years ago

A car is traveling at 25 miles per hour on a residential street. About how many feet does it travel per second?

Oksanka [162]

Answer:

Abt 37

Step-by-step explanation:

8 0

3 years ago

What is the length of a car if the length on the scale model car is 17 cm and the scale is 2 cm : 50 cm?

Zarrin [17]

Answers 425 is you multiply 50 by 8 you’d get 400 then add 25 the number 8 is the amount of times you can use the scale so it would be 16cm them you have one more cm left so you’d just cut the scale in half

3 0

3 years ago

Read 2 more answers

In Problems 23–30, use the given zero to find the remaining zeros of each function

Talja [164]

Answer:

x = 2i, x = -2i and x = 4 are the roots of given polynomial.

Step-by-step explanation:

We are given the following expression in the question:

$f(x) = x^3 - 4x^2+ 4x - 16$

One of the zeroes of the above polynomial is 2i, that is :

$f(x) = x^3 - 4x^2+ 4x - 16\\f(2i) = (2i)^3 - 4(2i)^2+ 4(2i) - 16\\= -8i+ 16+8i-16 = 0$

Thus, we can write

$(x-2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Now, we check if -2i is a root of the given polynomial:

$f(x) = x^3 - 4x^2+ 4x - 16\\f(-2i) = (-2i)^3 - 4(-2i)^2+ 4(-2i) - 16\\= 8i+ 16-8i-16 = 0$

Thus, we can write

$(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Therefore,

$(x-2i)(x+2i)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16\\(x^2 + 4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

Dividing the given polynomial:

$\displaystyle\frac{x^3 - 4x^2 + 4x - 16}{x^2+4} = x -4$

Thus,

$(x-4)\text{ is a factor of polynomial }x^3 - 4x^2 + 4x - 16$

X = 4 is a root of the given polynomial.

$f(x) = x^3 - 4x^2+ 4x - 16\\f(4) = (4)^3 - 4(4)^2+ 4(4) - 16\\= 64-64+16-16 = 0$

Thus, 2i, -2i and 4 are the roots of given polynomial.

4 0

3 years ago

Find the area of the regular polygon

olasank [31]

$area = 44.0467 \: cm {}^{2}$

<h3>step by step explanation </h3>

● area of regular polygon Formulas ,

⟹ $a = \frac{l^{2}n}{4tan(\frac{\pi }{n)}}$

● now finding the area of regular polygon,

⟹ $\frac{4 {}^{2} \times 8 }{ 4 \: tan \: \binom{180}{5} }$

⟹ $a = \frac{128}{4 \times 0.7265}$

⟹ $a = 44.0467 \: cm {}^{2}$

Hope it's helps you

4 0

3 years ago