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3 years ago

7

An object that starts at rest accelerates until it is moving at 247 km/h. If it takes 1.7 minutes for this change to occur what

is the average acceleration in m/s? 20 PTS!

1 answer:

fredd [130]3 years ago

6 0

I figured out the answer Chaseashley24! The answer to your question is:

0.673 m/s²

Hope this helps!

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Find m< AFE and include working out.

andreyandreev [35.5K]

Answer:

∠ AFE = 80°

Step-by-step explanation:

Since BD is a straight line , then

∠ AFB + ∠ AFE + ∠ EFD = 180°, that is

50° + ∠ AFE + 50° = 180°

100° + ∠ AFE = 180° ( subtract 100° from both sides )

∠ AFE = 80°

3 0

3 years ago

Plzz help me with this thank you in advance!!

olga nikolaevna [1]

Answer:

10.14

Step-by-step explanation:

6 0

3 years ago

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What are the solutions to the equation? x2 + 6x = 40

creativ13 [48]

Just plug in the numbers:

4: 16 + 24 = 40 YES

5 = 25 + 40 ≠ 40 NO

8: 64 + 48 ≠ 40 NO

10: 100 + 60 ≠ 40 NO

So A. is the correct answer. Just to be sure:

-10: 100 + ( - 60) = 40

Your answer is A. Hope that helps! :)

8 0

3 years ago

Read 2 more answers

Q6.4☆ Points: 2 Suppose that Angela wants to use her sample to create a 68% confidence interval for the true population median o

Andrei [34K]

Answer:

She needs a sample size of 25.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.68}{2} = 0.16$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.16 = 0.84$ , so Z = 0.995.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

The population SD is 2 grams.

This means that $\sigma = 2$

What is the minimum sample size she needs to create a confidence interval that has a width of 0.4 grams?

She needs a sample size of n.

n is found when M = 0.4. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.4 = 0.995\frac{2}{\sqrt{n}}$

$\sqrt{n} = \frac{0.995*2}{0.4}$

$(\sqrt{n})^2 = (\frac{0.995*2}{0.4})^2$

$n = 24.8$

Rounding up:

She needs a sample size of 25.

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2 years ago

What is the sum of x2+4x-2 and x2+5x+6

dolphi86 [110]

<span><span>(<span>x<span><span>2</span><span></span></span></span>−2<span>x<span><span>2</span><span></span></span></span>)+(4x+5x)+6</span><span>this is your answer
</span><span><span>−<span>x<span><span>2</span><span></span></span></span>+9x+6</span><span>
</span></span></span>

6 0

3 years ago