1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MrRissso [65]
4 years ago
7

Banks use negative balances to represent when the customer owes the bank money and positive balances to represent when the bank

owes the customer money.
Justin has a balance of 0 dollars at his local bank.

What does a balance of 0 dollars represent?

Justin owes the bank money.
The bank owes Justin money.
Neither Justin nor the bank owe each other money.
Justin gave half of his money to charity.
Mathematics
2 answers:
andre [41]4 years ago
8 0
I agree with her. Neither Justin nor the bank owe each other money.
<span />
likoan [24]4 years ago
7 0
<span>Neither Justin nor the bank owe each other money.</span>
You might be interested in
FIND THE AREA OF THE SHADED SECTION IN THE CIRCLE THE SHADED SECTION IS 35 DEGRESS AND THE RADIUS IS 5 INCHES. USE THE FORMULA:
Natali [406]

Answer:

Area of sector of circle = 7.6302 inches (Approx.)

Step-by-step explanation:

Given:

Angle of section = 35°

Radius of circle = 5 inch

Find:

Area of shaded section

Computation:

Area of shaded section  = Area of sector of circle

Area of sector of circle = [θ/360][πr²]

Area of sector of circle = [35/360][(22/7)(5)²]

Area of sector of circle = [0.0972][(3.14)(25)]

Area of sector of circle = [0.0972][78.5]

Area of sector of circle = 7.6302 inches (Approx.)

6 0
3 years ago
RT and UW are parallel lines
Veseljchak [2.6K]

Answer: ∡RSQ and ∡TSQ

Supplementary angles are angles that add up to 180 degrees. We can see in the picture that both angles are located on the same line, and no other angles are involved, so they must equal 180.

We can also use the process of elimination:

  • ∡RSQ and ∡UVS are congruent because they are consecutive angles.
  • ∡RSQ and ∡WVX are also congruent because they are alternate exterior angles.
  • ∡RSQ and ∡TSV are also congruent because they are vertical angles.

5 0
1 year ago
Answer this question please and thank you
Illusion [34]

Answer:

The first selection should be "all factors", and the second should be "only the prime factors."

Step-by-step explanation:

I'm guessing you already submitted your answers, since this question is a few days old, but in case someone looks at it later & needs it...

3 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
Which graph represents the function f(x) =-lx-2l-1​
zimovet [89]

It’s the second one from the right

Since there’s a - behind x it means it has to be facing down so it’s either 2 or 4

Now it’s x-2 and we know that x moves the opposite so it needs to move 2 to the right so the answer is 2

6 0
4 years ago
Other questions:
  • 2(2t+4)=34(24−8t). My math teacher is on crack
    15·2 answers
  • Given that f(x) =5x-10 qnd g(x) = 1/5 x+2 find (f×g)(x)​
    5·2 answers
  • 4x+5y-5z=196 -11x-7y+12z=-211 -8x-9y-z=-236 Solve for x y z
    13·2 answers
  • Do u know how to learn ur 11s and 12s fast
    13·2 answers
  • Please help!
    14·2 answers
  • Help with this question
    8·1 answer
  • These box plots show daily low temperatures for a sample of days in two
    11·1 answer
  • Is 3/5 bigger than 7/11
    5·1 answer
  • Is 60.560 an irrational number or rational?
    11·1 answer
  • HELP ME HELP<br><br>PLZ<br><br>PLZ<br><br>PLZ
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!