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3 years ago

K(n)=2n-2. find k(-4)

Mathematics

1 answer:

zlopas [31]3 years ago

4 0

-10 is the answer
Plug in -4 for n so 2x-4-2=-10

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Several students made comments about this image. A triangle has angles B, C, D. The exterior angle to angle B is A. Which commen

professor190 [17]

A Comment "If i know the measures of angles C and B, I can find the measures of A and D" is TRUE

Explanation :

If we know angles C and B we can find angles A and D as,

As from figure we know

A+B = 180°

∴ A = 180° - B ... we know B so we get A

Also,

B+C+D = 180° ... as BCD is a triangle

∴ D = 180° - (B+C) ... we know B and C so we get D

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Annette [7]

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3 years ago

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solmaris [256]

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3 years ago

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What is the equation of the axis of symmetry for the parabola y=1/2(x-3)^2+5

Rus_ich [418]

The general vertex form equation of the parabola is

$y=a(x-h)^2+k$

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x=h

For the given equation the Equation of the Axis of symmetry for the parabola y=1/2(x-3)^2+5 as x=3.

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3 years ago

The function f(x) = x is translated using the rule (x, y) - (x - 6, y + 9) to create A(x).

anyanavicka [17]

It seems the correct function you need to mention is f(x) = sqrt x

so, I am assuming $f(x) = \sqrt{x}$ and will solve the question based on it.

Answer:

Check the explanation

Step-by-step explanation:

Given the function

$f(x) = \sqrt{x}$

As the function is translated according to the rule

(x, y) → (x - 6, y + 9)

Translation of the function $f(x) = \sqrt{x}$ 6 units to the left will bring the function

$g(x) = \sqrt{x+6}$

Translation of the function $g(x) = \sqrt{x+6}$ 9 units up will bring the function

$A\left(x\right)=\sqrt{x+6}+9$

Determining the range of $A\left(x\right)=\sqrt{x+6}+9$

As we know that the range is the set of dependent values for which the function is defined.

$\mathrm{The\:range\:of\:an\:radical\:function\:of\:the\:form}\:c\sqrt{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k$

$k=9$

$f\left(x\right)\ge \:9$

$\mathrm{Range\:of\:}\sqrt{x+6}+9:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:9\:\\ \:\mathrm{Interval\:Notation:}&\:[9,\:\infty \:)\end{bmatrix}$

Therefore, the expression describes the range of A(x) will be:

$f\left(x\right)\ge \:\:9\:or\:y\:\ge \:\:\:9$

3 0

3 years ago