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FinnZ [79.3K]
3 years ago
6

Why is earth's core mostly made of iron

Chemistry
2 answers:
Triss [41]3 years ago
3 0
It is less dense than most other material and has a higher melting point so it will not melt.
Anvisha [2.4K]3 years ago
3 0

Answer:

Iron is a very dense element is the correct answer.

Explanation:

Earth's core mostly made of iron because Iron is a very dense element.

  • Iron is the heaviest metals and inclines toward the core of the earth.
  • The inner core is made up of hot and dense iron.
  • Iron is the most plentiful element via quantity in the Earth, constituting approximately 80 percent of the core( inner and outer) of  the Earth.
  • Iron is plentiful because of its nuclear durability in the nuclear fusion reaction.
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The structure of two compounds are shown: which statement is true?
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The first one. They are both alcohol groups

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How can a chemical reaction be compared to shuffling a deck of cards?
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The cards (matter) can be rearranged constantly, placed with others, the total or resent amount remains constant.

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Which examples are indirect evidence used to study Earth's interior? Check all that apply.
ch4aika [34]

<u>Answer</u>:

Indirect evidence used to study Earth's interior are

  • analysis of several seismographs  
  • location of an earthquake's epicentre  
  • identification of seismic wave direction

<u>Explanation</u>:

The earth is mainly divided into 3 layers. These are the crust, mantle and the core. Further, the interior part of the earth cannot be studied directly and the direct evidence explains the composition of rocks.

The seismic waves help with the understanding of indirect evidence. The seismic waves are the energy that travels through different layers of the earth.It is caused due to  volcanoes, earthquakes, landslides etc. Thus, analysis of several seismographs, identifying the direction the of seismic wave and location of earth’s epicentre helps to study earth's interior.  

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What is the pH of a mixture of equal volumes of 0.6 mM Lactic acid and 0.4 mM NaOH?
tino4ka555 [31]

Answer:

The pH of the mixture is approximately 4.2.

There's no equilibrium calculation involved if HCl is used instead of lactic acid. The pH of that solution will be approximately 3.7.

Explanation:

<h3>Lactic Acid</h3>

Lactic acid is a monoprotic acid. In other words, each lactic acid molecule can be ionized to release only one proton. Therefore, lactic acid will react with NaOH at a 1-to-1 ratio. The result will be one unit of the anion of lactate ion.

Lactic acid is in excess. All NaOH will be consumed. Before any dissociation takes place, the solution will contain 0.2 mM of lactic acid and 0.4 mM of lactate ions.

Lactic acid is a weak acid. The following equilibrium will take place in the solution:

\rm C_3H_6O_3 \leftrightharpoons {C_3H_5O_3}^{-} + H^{+}.

Let the increase in the concentration of protons in the solution be x\rm \;M. Construct a RICE table:

\begin{array}{c|ccccc}\rm \textbf{R}&\rm C_3H_6O_3 & \leftrightharpoons &\rm {C_3H_5O_3}^{-}& +& \rm H^{+}\\\textbf{I} & 0.2\times 10^{-3} && 0.4\times 10^{-3} \\\textbf{C} & -x & & +x & & +x\\\textbf{E} & 0.2\times 10^{-3} -x & & 0.4\times 10^{-3} + x & & x\end{array}.

The pKa value of lactic acid is 3.86. Therefore, K_{\rm a} = 10^{-3.86}. By the definition of the acid dissociation constant K_{\rm a},

\begin{aligned} K_{\rm a} &= \frac{\rm [H^{+}][{C_3H_5O_3}^{-}]}{[\rm C_3H_6O_3]}\\& = \frac{x(0.4\times 10^{-3} +x)}{(0.6 \times 10^{-3} - x)}\end{aligned}.

Given that K_{\rm a} = 10^{-3.86}, solve for x:

\displaystyle \frac{x(0.4\times 10^{-3} - x)}{0.2 \times 10^{-3}-x} = 10^{-3.86}.

There might be more than one solutions. However, the correct solution shall ensure that all concentrations are greater than zero. In this case,

x \approx 5.7\times 10^{-5}.

By the definition of pH,

\rm pH = -\log_{10}{[H^{+}]} = -\log_{10}{5.7\times 10^{-5}} \approx 4.2.

The Henderson-Hasselbalch equation will yield a similar result.

<h3>HCl</h3>

Similar to lactic acid, HCl is also monoprotic. The solution will contain 0.2 mM of HCl and 0.4 mM of NaCl before any ionization takes place.

Unlike lactic acid, all that 0.2 mM of HCl will ionize to produce protons and chloride ions. The final proton concentration in the solution will be 0.2 mM. As a result,

\rm pH = - \log_{10}{[H^{+}]} = -\log_{10}{0.2\times 10^{-3}} \approx 3.6.

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