Answer:
Correct Answer is C(−5 ±square root 6)
Step-by-step explanation:
2x^2+20x+38=0
2(x^2+10x+19)=0
x^2+10x+19=0
This is a quadratic equation here we have used following formula to find the roots of this equation
x=-b−±square root (b^2-4*a*c))/2*a......(1)
Here,
a=1
b=10
c=19
put values of a, b and c in equation (1)
x=(-10 ±square root(10^2-4*1*19))/2*1
x=(-10 ±square root(100-76))/2
x=(-10 ±square root(24))/2
x=(-10 ±square root(2*2*6))/2
x=(-10 ±2square root(6))/2
x=2(-5 ±square root(6))/2
x=-5 ±square root(6)
Hope this answer will help you
They are all integers so...
first lets substitute
A.3x=13
X=13/3
b.3x+2=13
3x=11
x=11/3
c.3x+4=13
3x=9
x=3
d.3x+6=13
3x=7
x=7/3
E.3x+8=13
3x=5
x=5/3
therefore the possible is letter c because it must be an integer and the definition of integer states that it is not a decimal nor a fraction
Answer: d because im big brain
Step-by-step explanation:
Answer:
Given : s||t
Exterior sides in opposite rays : ∠5 and ∠7 are supplementary
Definition of supplementary angles : m∠5 + m∠7 = 180°
If lines are ||, corresponding angles are equal : m∠1 = m∠5
Substitution : m∠1 + m∠7 = 180°
Answer:
Step-by-step explanation:
1st draw 3 circles where each center is on one of the points, and the other side , the drawing side of the compass is on another point.. the draw the circle ... do that for each point... there will be one point.. where all three cross some where in the middle.. put the point of your compass on that point.. and then put the drawing side on any one of the points... all 3 will now be on the circle.. draw it.. :)
