Graph the function f(x)=2(2)^x for -3<=x<=2.
1 answer:
See attached graph (from -4<=x<=2 )
The y-intercept is the multiplier to the exponential, i.e. 2.
The graph goes from (-3,1/4) to (2, 8), so the range in interval notation is [1/4,8]
If f(x)=2(3^x), then the y-intercept stays the same at 2. The graph goes from (-3, 2/27) to (2,18), and the corresponding range will be [2/27, 18].
See second graph for more information.
The y-intercept is the multiplier to the exponential, i.e. 2.
The graph goes from (-3,1/4) to (2, 8), so the range in interval notation is [1/4,8]
If f(x)=2(3^x), then the y-intercept stays the same at 2. The graph goes from (-3, 2/27) to (2,18), and the corresponding range will be [2/27, 18].
See second graph for more information.
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Answer: you will win for any distances greater than 190ft.
To find the rate, you’ll first need to find the slope between two points
Slope formula: m=y^2 - y^1 / x^2 - x^1
Plug the equation in: 76-38/4-2
Substitute. subtract, & divide and you get m=19
Then you have to do slop intercept form:
Formula: y-y1= m(x-x1)
Plug in the equation:
Y-38=19(x-2) substitute
Y-38=19-38 distribute
Y= 19x
Then you graph it (I attached a graph pic)
On the graph there’s two lines that intersect at (10,190). For x less than 10, you will run farther than your friends = you will win.
To find the rate, you’ll first need to find the slope between two points
Slope formula: m=y^2 - y^1 / x^2 - x^1
Plug the equation in: 76-38/4-2
Substitute. subtract, & divide and you get m=19
Then you have to do slop intercept form:
Formula: y-y1= m(x-x1)
Plug in the equation:
Y-38=19(x-2) substitute
Y-38=19-38 distribute
Y= 19x
Then you graph it (I attached a graph pic)
On the graph there’s two lines that intersect at (10,190). For x less than 10, you will run farther than your friends = you will win.