All categories

3 years ago

Rounding decimalsrounding decimals

1 answer:

4 0

If your asking what is it its
When rounding to a place to the right of the decimal point, drop all the numerals to the right of the rounding place instead of changing them to zeros. Thus, 567.235 rounded to the nearest ten is 570, and 567.235 rounded to the nearest tenth is 567.2
If I'm wrong I'm sorry

You might be interested in

The Human Resources manager at a company records the length

luda_lava [24]

Answer:

the correct answer is 0.84

give brainliest plzzz

6 0

4 years ago

What are the first 4 terms in the sequence represented by the expression 2n+3

torisob [31]

The answer would be A

5 0

4 years ago

Read 2 more answers

Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.

Romashka [77]

Answer:

(3,7) (7,3) (−1,14) (0,1) (12,25)

(5,11) (0,12) (1,8) (12,0) (−1,−1)

Step-by-step explanation:

We have the following function:

$y = 2x+1$ .

We are going to check if each ordered pair is a solution.

(3,7)

If when $x = 3, y = 7$ , it is a solution.

$y = 2x + 1 = 2(3) + 1 = 7$

This ordered pair is a solution.

(7,3)

If when $x = 7, y = 3$ , it is a solution.

$y = 2x + 1 = 2(7) + 1 = 15$

This ordered pair is not a solution.

(-1,14)

If when $x = -1, y = 14$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is not a solution.

(0,1)

If when $x = 0, y = 1$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is a solution.

(12,25)

If when $x = 12, y = 25$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is a solution.

(5,11)

If when $x = 5, y = 11$ , it is a solution.

$y = 2x + 1 = 2(5) + 1 = 11$

This ordered pair is a solution.

(0,12)

If when $x = 0, y = 12$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is not a solution.

(1,8)

If when $x = 1, y = 8$ , it is a solution.

$y = 2x + 1 = 2(1) + 1 = 3$

This ordered pair is not a solution.

(12,0)

If when $x = 12, y = 0$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is not a solution.

(-1,-1)

If when $x = -1, y = -1$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is a solution.

3 0

3 years ago

if two fractions have the same denominator but different new Mary which fraction is greater? Give an example

german

It would be the one with the greater numerator 6/6 would be greater than 5/6

5 0

4 years ago

HEEEEELP!!!!!!!!!!!!!11 I WILL MARK BRAINLIEST kx-3y=4 4x-5y=7 k is constant and x and y are variables, for what value of k will

Studentka2010 [4]

Answer:

Step-by-step explanation:

There is no solution for system of equations: $a_1x+b_1y=c_1\\a_2y+b_2y=c_2$

if: $a_1=a_2\quad and\quad b_1=b_2\quad and\quad \bold{c_1\ne c_2}$

so first, we we need to transform the equations to the form where the coefficients at y will be the same:

$kx-3y=4\\ 4x-5y=7\\\\ (kx-3y)\cdot5=4\cdot5\\ (4x-5y)\cdot3=7\cdot3\\\\ 5kx-15y=20\\ 12x-15y=21$

Now we have b₁=b₂ and c₁≠c₂ so the system has no solution if a₁=a₂

5k = 12

÷5 ÷5

k = ¹²/₅

7 0

3 years ago