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QveST [7]
3 years ago
11

I NEED HELP!!!! I am currently reviewing for my last test, and i am struggling with this problem. I KNOW WHAT THE ANSWER IS BUT

I NEED TO KNOW HOW TO SOLVE IT> We reward lots of points if solves it in explaination. :)
Here is the question!: Find the surface area of the following triangular prism.

Mathematics
1 answer:
stira [4]3 years ago
4 0

Answer:

336\:\mathrm{ft^2}

Step-by-step explanation:

The total surface area simply consists of three rectangles and two triangles. To find the total surface of the figure, find the sum of each of the shapes that make up the outside of the figure:

2 triangles: 2 x 1/2 x 6 x 8 = 48 ft^2

First rectangle: 6 x 12 = 72 ft^2

Second rectangle: 8 x 12 = 96 ft^2

Third rectangle: 10 x 12 = 120 ft^2

*Note: One of the dimensions is in yards, so make sure to convert it to ft (1 yd = 3ft)

Thus, the total surface area of the figure is 48+72+96+120 = 336 ft^2.

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A

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yes it is A

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IM GIVEN BRAINLIEST!! :)
kiruha [24]

Answer: 975.

A 28% discount makes 702 72% of the original price, so 702/.72 gives 975

Hope this helps :)

8 0
2 years ago
Which statements are true? Select the two correct answers.
denpristay [2]

Answer:

5.the square root is positive number lessthan 1 is beteween 0 and 1

1.the square root of a positive number greater than 1 is less thsn number

8 0
3 years ago
The sum of 2 numbers is 46. One number is 12 more than the other. What are the numbers?
harkovskaia [24]

Answer:

two numbers are 29 and 17

Step-by-step explanation:

let the number be x

12+x+x=46

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5 0
3 years ago
Read 2 more answers
A bee flies 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for fifteen minutes. Then i
Ksenya-84 [330]

A. The equation to find the distance of the flowerbed from the hive is: \frac{x}{20}+\frac{x}{12}+900= 1200 , where x is the distance.

B.  The flowerbed is 2250 feet far from the hive.

<u><em>Explanation</em></u>

Suppose, the distance of the flowerbed from the hive is x feet.

The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.

As, Time=\frac{Distance}{Speed}

So, the time taken by the bee to reach the flowerbed = \frac{x}{20} seconds and the time taken to fly back to the hive =\frac{x}{12} seconds.

The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.

So, the equation will be.......

\frac{x}{20}+\frac{x}{12}+900= 1200\\ \\ \frac{3x+5x}{60}= 300\\ \\ 8x= 60*300\\ \\ 8x=18000\\ \\ x=\frac{18000}{8}=2250

Thus, the distance of the flowerbed from the hive is 2250 feet.

5 0
3 years ago
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