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3 years ago

54 1/4% equals _____

Mathematics

1 answer:

tresset_1 [31]3 years ago

8 0

The answer to the question

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figure abcd is similar to figure mnkl if ab = 2x + 1, bc= 12, mn = 8, nk=7 and kl=13, what is the value of x

Kruka [31]

Step-by-step explanation:

are this form 1 question??

4 0

3 years ago

(3 + 4i) - (8 -5i) Write answer in standard form a +bi Group of answer choices

Anton [14]

Answer:

$A=-5+9i$

Step-by-step explanation:

$\left(3+4i\right)-\left(8-5i\right)\\\\\mathrm{Group\:the\:real\:part\:and\:the\:imaginary\:part\:of\:the\:complex\:number}\\\left(a+bi\right)\pm \left(c+di\right)=\left(a\:\pm \:c\right)+\left(b\:\pm \:d\right)i\\\\=\left(3-8\right)+\left(4+5\right)i\\3-8=-5\\4+5=9\\\\=-5+9i$

5 0

3 years ago

How do you solve this btw it’s gr11 applied

Georgia [21]

Answer:62

Step-by-step explanation: 62

3 0

3 years ago

. A recent report in a women magazine stated that the average age for women to marry in the United States is now 25 years of age

Setler [38]

Answer: 0.0136

Step-by-step explanation:

Given : Mean : $\mu=25$

Standard deviation : $\sigma=3.2$

Sample size : $n=50$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

For x = 24

$z=\dfrac{24-25}{\dfrac{3.2}{\sqrt{50}}}=-2.21$

The p-value = $P(z\leq-2.21)= 0.0135526\approx0.0136$

Hence, the probability that the sample mean age for 50 randomly selected women to marry is at most 24 years = 0.0136

3 0

3 years ago

A certain organization recommends the use of passwords with the following format: vowel commavowel, consonant comma consonant c

zimovet [89]

The password format is = inpray93

vowel , consonant, consonant, consonant, vowel, consonant, number, number.

There are 21 consonants, 5 vowels and 10 number choices (0-9)

Since, there are 21 consonants and repetition is allowed so for 2nd, 3rd, 4th, and 6th positions 21 choices are available. For 1st and 5th positions, 5 choices are available and for 7th and 8th position there are 10 choices (0 to 9).

Passwords are not case sensitive which means upper case and lower case letters are same.

So, the number of passwords can be =

$5\times21\times21\times21\times5\times21\times10\times10$

= 486202500

Part (b) question is not given. But it can be opposite to the first part i.e when the password letters are case sensitive.

This means all the letters are different.

So, number of passwords will be =

$10\times42\times42\times42\times10\times42\times10\times10$

= 31116960000

4 0

3 years ago