Answer:
The area of the parallelogram is 20 units²
Step-by-step explanation:
* Lets explain how to solve the problem
- The vertices of the parallelogram are (0 , -2) , (3 , 2) , (8 , 2) , (5 , -2)
- The side joining the points (0 , -2) and (5 , -2) is a horizontal side
because the points have same y-coordinates
- The side joining the points (3 , 2) and (8 , 2) is a horizontal side
because the points have same y-coordinates
∴ These two sides are parallel bases of the parallelogram
∵ The length of any horizontal side = x2 - x1
∴ The length of the side = 5 - 0 = 5 <em>or</em> 8 - 3 = 5
∴ The length of one base of the parallelogram is 5 units
- The height of this base is the vertical distance between these two
parallel bases
∵ The length of any vertical distance = y2 - y1
∵ y2 = 2 and y1 = -2 ⇒ the y-coordinates of the parallel bases
∴ The length of the vertical distance = 2 - (-2) = 2 + 2 = 4 units
∵ This vertical distance between the two parallel bases is the height
of these bases
∴ The height of the parallelogram is 4 units
- The area of the parallelogram = base × height
∵ The base = 5 units and the height = 4 units
∴ The area = 5 × 4 = 20 units²
* The area of the parallelogram is 20 units²
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