Answer:
(7+Z)²
Step-by-step explanation:
A less ambiguous way to describe the quantity might be "the square of the quantity seven plus Z".
As it is, we rely on the presence of the comma to tell us that the quantity to be squared is (7+Z). If the comma were not present, we would assume you want to add 7 to the square of Z: 7+Z².
the quantity 7 plus Z: (7+Z)
that quantity squared: (7+Z)²
Answer: You will need to find the x-intercepts and the vertex
Step-by-step explanation: Use the information in the factors and some formulae.
The x- intercepts are the points where the parabola crosses the x-axis. The x-axis is where y = 0
Set each factor equal to 0 and solve:
x-2=0, so x = +2 and x +4 = 0, so x = -4 (you would plot these if creating the graph)
To find the vertex you need the Vertex Formula: x = -b/2a
b is the coefficient of the x term in the middle of the quadratic equation; you can just do the O and I parts of FOIL to get b: -2x + 4x = 2x You know a = 1 because x² will have the implied (missing)(1).
Put the numbers in the Formula: x = -b/2a x = -(2)/2(1) -2/2 = -1
-1 is the "x-value" of the vertex.
The y value is the 'c' in the quadratic formula. You get that from the L part of FOIL -2 × 4 = -8 .
So, your coordinates for the vertex: ( -1, -8 )
If you were creating a graph, you would plot that point, then draw the parabola starting there and through the x-intercepts.
Answer:
6
General Formulas and Concepts:
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
9b⁶c⁵
<u>Step 2 Identify</u>
Our largest degree is the variable raised to the highest exponent.
b⁶ > c⁵
Therefore our degree is 6.
9514 1404 393
Answer:
5 hours
Step-by-step explanation:
A quick way to look at this is to compare the difference in hourly charge to the difference in 0-hour charge.
The first day, the charge is $3 more than $12 per hour.
The second day, the charge is $12 less than $15 per hour.
The difference in 0-hour charges is 3 -(-12) = 15. The difference in per-hour charges is 15 -12 = 3. The ratio of these is ...
$15/($3/h) = 5 h
The charges are the same after 5 hours.
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If you write equations for the charges, they will look like ...
y1 = 15 + 12(x -1)
y2 = 3 + 15(x -1)
Equating these charges, we have ...
15 +12(x -1) = 3 + 15(x -1)
12x +3 = 15x -12 . . . . . . . . eliminate parentheses
15 = 3x . . . . . . . . . . add 12-12x
x = 15/3 = 5 . . . . . . divide by 3
You might notice that the math here is very similar to that described in words, above.
The charges are the same after 5 hours.
Answer:
(-3,5)
Step-by-step explanation:
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