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Based on the scenario above about the leading-trailing system Both technician A and B are incorrect.
<h3>How many brake shoes function?</h3>
There are known to be two shoes function that are said to be working a way where both become either the trailing shoe or leading shoe based on whether the vehicle is moving forward or backward.
Therefore we can say that, Based on the scenario above about the leading-trailing system Both technician A and B are incorrect.
Learn more about trailing system from
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Answer:
Please kindly check explainations for the code.
Explanation:
lw $t1, Num1
lw $t2, Num2
lw $t3, Num3
blt $t1, $t2, if
beq $t1, $t2, elseif
else:
add $t0, $t3, 5
sw $t0, Result
endif:
#.....other statements after if-elseif-else
if:
sw $t1, Result
b endif
elseif:
ble $t2, $t3, if2
or $t0, $t1, $t3
sw $t0, Result
b endif
if2:
and $t0, $t2, $t3
sw $t0, Result
b endif
Go to attachment for the onscreen code.
Answer:
loop
Explanation:
Loop is the one which is used to execute the specific statement again and again until the condition is true.
In the programming, there are 3 basic loop used.
1. for loop
<u>Syntax:</u>
for(initialization, condition, increment/decrement)
{
statement;
}
the above statement execute until the condition in the for loop true when it goes to false, the loop will terminate.
2. while loop
<u>Syntax:</u>
initialization;
while(condition)
{
statement;
increment/decrement;
}
it is work same as for loop and the increment/decrement can be write after or before the statement.
3. do while
syntax:
initialization;
do
{
statement;
increment/decrement;
}while(condition);
here, the statement execute first then, it check the condition is true or not.
so, if the condition is false it execute the statement one time. this is different with other loops.
Answer:
#include <iostream>
using namespace std;
int * reverse(int a[],int n)//function to reverse the array.
{
int i;
for(i=0;i<n/2;i++)
{
int temp=a[i];
a[i]=a[n-i-1];
a[n-i-1]=temp;
}
return a;//return pointer to the array.
}
int main() {
int array[50],* arr,N;//declaring three variables.
cin>>N;//taking input of size..
if(N>50||N<0)//if size greater than 50 or less than 0 then terminating the program..
return 0;
for(int i=0;i<N;i++)
{
cin>>array[i];//prompting array elements..
}
arr=reverse(array,N);//function call.
for(int i=0;i<N;i++)
cout<<arr[i]<<endl;//printing reversed array..
cout<<endl;
return 0;
}
Output:-
5
4 5 6 7 8
8
7
6
5
4
Explanation:
I have created a function reverse which reverses the array and returns pointer to an array.I have also considered edge cases where the function terminates if the value of the N(size) is greater than 50 or less than 0.
