Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
Answer: ....
Big Data
Explanation:
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Answer:
For the first picture, choose the second pair, and for the second one, choose the first pair
Explanation:
You need to attach a document of where i would read it from
Answer:
All of Given
Explanation:
The throw keywords can be used to throw any Throwable object. The syntax is :
throw <Throwable instance>
Note that Error and Exception are subclasses of Throwable while RuntimeException is a subclass of Exception. So the hierarchy is as follows:
Throwable
-- Error
-- Exception
-- RuntimeException
And all of these are valid throwable entities. As a result "All of Given" is the most appropriate option for this question.