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Rama09 [41]
3 years ago
7

Calculate the sample standard deviation of data from Question 1 76,45,64,80,92

Mathematics
1 answer:
mash [69]3 years ago
6 0

Answer:

S.D = 15.98

Step-by-step explanation:

Given: 76,45,64,80,92

Required: Determine the standard deviation

We start by calculating the mean

Mean = \frac {\sum x}{n}

Where x-> 76,45,64,80,92 and n = 5

Mean = \frac {76+45+64+80+92}{5}

Mean = \frac{357}{5}

Mean = 71.4

Subtract Mean (71.4) from each of the given data

76 - 71.4 = 4.6\\45 - 71.4 = -26.5\\64 - 71.4 = -7.4\\80 - 71.4 = 8.6\\92 - 71.4 = 20.6

Determine the absolute value of the above result

|4.6| = 4.6\\|-26.5| = 26.5\\|-7.4| = 7.4\\|8.6| = 8.6\\|20.6| = 20.6

Square Individual Result

4.6^2 = 21.16 \\26.5^2 = 702.25\\7.4^2 = 54.76\\8.6^2 = 73.96\\20.6^2 = 424.36

Calculate the mean of the above result to give the variance

Mean = \frac {\sum x}{n}

Mean = \frac{21.16 + 702.25 + 54.76 + 73.96 + 424.36}{5}\\Mean = \frac{1276.49}{5}\\Mean = 255.298

Hence, Variance = 255.298

Standard Deviation is calculated by \sqrt{Var}

SD = \sqrt{255.298}

S.D = 15.9780474402

S.D = 15.98 (Approximated)

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If your financial goal is to save at least $40,000 in 10 years, what would be the least
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<em><u>The least amount of money you would need to invest per month is; $335</u></em>

<em><u>The anticipated rate of return on your investments is; 7%</u></em>

<em><u /></em>

  • Amount to have been saved at the end of 10 years ≥ $40,000

Number of years of savings = 10 years.

  • We want to find out the least amount to be invested per month.

There are 12 months in a year. Number of months in 10 years = 10 × 12 = 120 months.

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Thus;

Monthly savings ≈ $335

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4 0
2 years ago
What is the sum or difference?
dlinn [17]
1. Ans: Option (B) -6x^4

Explanation:
Given: 2x^4 - 8x^4
Take the common out:
=> x^4(2 - 8)

Hence: => [tex]-6x^4[/tex] (Option B)

2. Ans: Option (D) -3y^5

Explanation:
Given: 6y^5 - 9y^5
Take the common term(s) out:
=> y^5(6-9)

Hence: => -3y^5 (Option D)

3. Ans: Option (B) 9x^2 - 12x + 6<span> quadratic trinomial 

Explanation:
</span>Given: 6 - 12x + 13x^2 - 4x^2

The standard form of polynomial function must have the highest powered value at the start, then the second highest and so on.

=> 
13x^2 - 4x^2 - 12x + 6
=> 9x^2 - 12x + 6 (Option B)

4. Ans: Option (C) 7.3x^2 + 0.8x + 1.3

Explanation:
In order to find the total number of C<span>ommon and Endler's guppies, you need to add both Common and Endler's guppies' polynomials, as follows:

</span>Common guppies: 3.1x^2 +6.0x + 0.3<span>
Endler's guppies:   </span>4.2x^2 - 5.2x + 1.0
(add both)
-----------------------------------------------------------------
Total number:          7.3x^2 +0.8x + 1.3
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Hence the ans is Option(C) 7.3x^2 + 0.8x + 1.3

5. Ans: Option (D) 2x^2(133 - 18 \pi )

Explanation:
First let's find the total area of the yard:
Total Area of the Yard = 14x * 19x = 266x^2

Now the area of the circular fountain:
Area of the Circular Fountain = \pi r^2
Since, r=6x
Therefore,
Area of the Circular Fountain = \pi (6x)^2 = 36 \pi x^2

Now the final Area of the yard would be:
Final area of the Yard = Total Area of the Yard - Area of the Circular Fountain
Final area of the Yard = 266x^2 - 36 \pi x^2
=> Final area of the Yard = 2x^2(133 - 18 \pi) (Option D)

6. Ans: Option (A) 56x^2

Explanation:
First let's find the total area of the lot:
Total Area of the lot= 6x * 10x = 60x^2

Now the area of the stadium:
Area of the stadium = 1x * 4x = 4x^2

Now the final Area of the lot would be:
Final area of the lot= Total Area of the lot - Area of the stadium
Final area of the lot= 60x^2 - 4x^2
=> Final area of the lot = 56x^2 (Option A)

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